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| Excel Questions All Excel/VBA questions - formulas, macros, pivot tables, general help, etc. Please post to this forum in English only. |
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#1 |
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Join Date: Sep 2002
Posts: 2
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I have a list of numbers which are normally distributed. I want to assign a standard score to each number. eg for a number which was exactly on the avaerage I want a standard score of 100. For a number which is right at the bottom extreme I want a standard score of 69.
Any ideas?
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Hope you can help |
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#2 | |
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Join Date: Aug 2002
Posts: 34
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I am not sure what you want exactly. A common way of giving a 'score' to a series of normally distributed numbers is to substract the average and divide by the standard deviation. i.e.
B1=(A1-average(A$1:A$50))/stdev(A$1:A$50) and pulling down to B50 This gives a value of 0 to the average. On average, around 68% of the values will be between -1 and +1 and 95% between -2 and +2. In your example, I can understand you want to set 100 as being the average, but what do you mean the 'bottom extreme', and why set it at 69? Quote:
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#3 |
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Join Date: Sep 2002
Posts: 2
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Thanks - yes I understand.
I thought that with a standard score table, the mean is 100, 68% of the values lie between 85 and 115, and 95 % of the values lie between 70 and 130. I wanted to ascribe a standard score, based on the above, to all my numbers. (Hence my request that the bottom 2.5% have a standard score of 69) Any ideas? |
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#4 | |
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Join Date: Aug 2002
Posts: 34
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What you are speaking is then a normal distribution with average 100 and standard deviation 15. To get this score, you can just do
B1=100+15*(A1-average(A$1:A$50))/stdev(A$1:A$50) and pull down the formula Quote:
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