MrExcel Message Board


Go Back   MrExcel Message Board > Question Forums > Excel Questions

Excel Questions All Excel/VBA questions - formulas, macros, pivot tables, general help, etc. Please post to this forum in English only.

Reply
 
Thread Tools Display Modes
Old Sep 12th, 2002, 09:27 AM   #1
verdon
 
Join Date: Sep 2002
Posts: 2
Default

I have a list of numbers which are normally distributed. I want to assign a standard score to each number. eg for a number which was exactly on the avaerage I want a standard score of 100. For a number which is right at the bottom extreme I want a standard score of 69.

Any ideas?
__________________
Hope you can help
verdon is offline   Reply With Quote
Old Sep 12th, 2002, 10:36 AM   #2
Joel Horowitz
 
Join Date: Aug 2002
Posts: 34
Default

I am not sure what you want exactly. A common way of giving a 'score' to a series of normally distributed numbers is to substract the average and divide by the standard deviation. i.e.
B1=(A1-average(A$1:A$50))/stdev(A$1:A$50)
and pulling down to B50
This gives a value of 0 to the average. On average, around 68% of the values will be between -1 and +1 and 95% between -2 and +2.

In your example, I can understand you want to set 100 as being the average, but what do you mean the 'bottom extreme', and why set it at 69?

Quote:
On 2002-09-12 03:27, verdon wrote: I have a list of numbers which are normally distributed. I want to assign a standard score to each number. eg for a number which was exactly on the avaerage I want a standard score of 100. For a number which is right at the bottom extreme I want a standard score of 69. Any ideas?
Joel Horowitz is offline   Reply With Quote
Old Sep 12th, 2002, 01:09 PM   #3
verdon
 
Join Date: Sep 2002
Posts: 2
Default

Thanks - yes I understand.

I thought that with a standard score table, the mean is 100, 68% of the values lie between 85 and 115, and 95 % of the values lie between 70 and 130. I wanted to ascribe a standard score, based on the above, to all my numbers. (Hence my request that the bottom 2.5% have a standard score of 69)

Any ideas?
verdon is offline   Reply With Quote
Old Sep 12th, 2002, 09:01 PM   #4
Joel Horowitz
 
Join Date: Aug 2002
Posts: 34
Default

What you are speaking is then a normal distribution with average 100 and standard deviation 15. To get this score, you can just do
B1=100+15*(A1-average(A$1:A$50))/stdev(A$1:A$50)
and pull down the formula

Quote:
On 2002-09-12 07:09, verdon wrote:
Thanks - yes I understand.

I thought that with a standard score table, the mean is 100, 68% of the values lie between 85 and 115, and 95 % of the values lie between 70 and 130. I wanted to ascribe a standard score, based on the above, to all my numbers. (Hence my request that the bottom 2.5% have a standard score of 69)

Any ideas?
Joel Horowitz is offline   Reply With Quote
Reply

Bookmarks

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is On

Forum Jump


All times are GMT +1. The time now is 05:57 AM.


Powered by vBulletin® Version 3.8.4
Copyright ©2000 - 2009, Jelsoft Enterprises Ltd.
All contents Copyright 1998-2009 by MrExcel Consulting.