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| Excel Questions All Excel/VBA questions - formulas, macros, pivot tables, general help, etc. Please post to this forum in English only. |
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#1 |
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New Member
Join Date: May 2002
Location: Broward Sheriffs Office
Posts: 3
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I work as a GIS Administrator for a law enforcement agency. To assist the various divisions, i geocode (address match) various address databases to a street network which contains address range information.
The problem is that the databases containing Street names that are numbers are just that (i.e., 1, 2, 33, etc). I need to format them so they are in the following format: 1st, 2nd, 3rd. By the way they parse the addresses like so: Prefix Street_no Streetname Street_type SW 1230 1 Ave The streetname 1 should be 1st not 1 Is there a solution other than search and replace every single number type. What i do know is that the address name that are numbers only go up to 300. Thus, width is three digit number the ideal situation would be to create some type of logical statement where ?0 equals ?0th this would replace all numbers such as 10th, 20th, 30th...90th" I am more GIS savvy than excel but i am willing to learn if there are any solutions to this problem. I will continue to go through the archive to see if this has already been addressed (no pun intended). But any advice would be great |
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#2 |
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Board Regular
Join Date: Feb 2002
Posts: 3,065
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OK this is going to be tough, law man eh! OK so no point asking to much i know this from my agency days "county courts"
now run with me assume you had a date, which in the 1 2 3 or to 31 need the correct end i.e. st nd rd th now then if so the street is it need to be the day so I can force excel to go xxxxxxx 1st xxx if so can I ask silly questions, US say zip? I don’t read them or understand them, need some help, who are they made up.. do they follow pattern. Please give few examples, I have a plan.. I’m not promising thou:
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Free Excel based Web Toolbar available here. Jack in the UK J & R Excel Solutions "making Excel work for you" |
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#3 |
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MrExcel MVP
Join Date: Feb 2002
Location: Monterrey, Mexico
Posts: 1,433
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Try the following code:
Sub FormatNumbers() Dim SecondText As Variant Dim OriginalText As String, FirstText As String, ThirdText As String Dim PrevSpace As Integer, NextSpace As Integer, LastSpace As Integer For Each cell In Selection OriginalText = cell.Value & " " PrevSpace = 0 NextSpace = 0 LastSpace = 0 Do PrevSpace = Application.WorksheetFunction.Search(" ", OriginalText, PrevSpace + 1) NextSpace = Application.WorksheetFunction.Search(" ", OriginalText, PrevSpace + 1) LastSpace = Application.WorksheetFunction.Search(" ", OriginalText, NextSpace + 1) Loop Until LastSpace = Len(OriginalText) OriginalText = cell.Value FirstText = Left(OriginalText, PrevSpace) ThirdText = Right(OriginalText, Len(OriginalText) - NextSpace) SecondText = Mid(OriginalText, PrevSpace + 1, NextSpace - 1 - PrevSpace) If SecondText = 1 Then SecondText = "1st " ElseIf SecondText = 2 Then SecondText = "2nd " ElseIf SecondText = 3 Then SecondText = "3rd " Else: SecondText = SecondText & "th " End If cell.Value = FirstText & SecondText & ThirdText Next cell End Sub You have to select the cell or cells that you want changed and then run the macro. Edit as needed. _________________ Hope this helps. Kind regards, Al. [ This Message was edited by: Al Chara on 2002-05-14 13:34 ] |
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#4 |
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Board Regular
Join Date: Feb 2002
Posts: 3,065
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Love that code do you mind if i archive that one very sweet, but can iask the question was 1 2 3 and 33 so SORRY i have asked about US zips, but im lost i can add in 33 hassle free if there are 4 to 32 >>>>
>>>>>>>>>>>>>>>>?????????????????? that’s some code, i have a plan for this and so ask, but i not going to type 2500 variables. IF us are 1 2 3 why ask 33? and what about 10th 11th 12th there’s no th can you advise me please,,,
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Free Excel based Web Toolbar available here. Jack in the UK J & R Excel Solutions "making Excel work for you" |
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#5 |
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MrExcel MVP
Join Date: Feb 2002
Location: Monterrey, Mexico
Posts: 1,433
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Thanks Jack,
I really didn't test the code for a lot of different numbers. The following should work now. Please post with further questions. Dim SecondText As Variant Dim OriginalText As String, FirstText As String, ThirdText As String Dim PrevSpace As Integer, NextSpace As Integer, LastSpace As Integer For Each cell In Selection OriginalText = cell.Value & " " PrevSpace = 0 NextSpace = 0 LastSpace = 0 Do PrevSpace = Application.WorksheetFunction.Search(" ", OriginalText, PrevSpace + 1) NextSpace = Application.WorksheetFunction.Search(" ", OriginalText, PrevSpace + 1) LastSpace = Application.WorksheetFunction.Search(" ", OriginalText, NextSpace + 1) Loop Until LastSpace = Len(OriginalText) OriginalText = cell.Value FirstText = Left(OriginalText, PrevSpace) ThirdText = Right(OriginalText, Len(OriginalText) - NextSpace) SecondText = Mid(OriginalText, PrevSpace + 1, NextSpace - 1 - PrevSpace) If SecondText = 11 Then SecondText = "11th " ElseIf SecondText = 12 Then SecondText = "12th " ElseIf SecondText = 13 Then SecondText = "13th " ElseIf Right(SecondText, 1) = 1 Then SecondText = SecondText & "st " ElseIf Right(SecondText, 1) = 2 Then SecondText = SecondText & "nd " ElseIf Right(SecondText, 1) = 3 Then SecondText = SecondText & "rd " Else: SecondText = SecondText & "th " End If cell.Value = FirstText & SecondText & ThirdText Next cell
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Kind regards, Al Chara |
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#6 |
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Board Regular
Join Date: Feb 2002
Posts: 3,065
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Ok i see it matters not, this is my way of thinking hope you did not mind me asking, but i was a tad lost not hot on US never been
cheers mate i like this a lot ill let you know if my cunning plan works
__________________
Free Excel based Web Toolbar available here. Jack in the UK J & R Excel Solutions "making Excel work for you" |
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#7 |
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MrExcel MVP
Join Date: Feb 2002
Location: Monterrey, Mexico
Posts: 1,433
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Jack,
The example in question, "SW 1230 1 Ave", does not include a US zip code. It basically is saying the address is 1230 SouthWest 1st Avenue. ZIP is an acronym for Zone Improvement Plan. A ZIP Code is a 5-digit code that identifies a specific geographic delivery area. ZIP Codes can represent an area within a state (an area that may or may not cross county boundaries), an area that crosses state boundaries (an unusual condition), or a single building or company that has a very high mail volume.
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Kind regards, Al Chara |
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#8 |
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New Member
Join Date: May 2002
Location: Broward Sheriffs Office
Posts: 3
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Al,
Thanks for the macro, i am sort of new with macros...when it comes to Excel i tend to work hard rather than work smart by performing manual processes. I copied your macro as new macro which called NumbersFormat. I selected the appropriate column and ran the macro but it found an error in the line NextSpace = Application.WorksheetFunction.Search(" ", OriginalText, PrevSpace + 1) I appreciate your assistance, i sent you a sample copy of what i am up against if you wanted to run the macro and test it. As a macros novice i am not sure what the problem could be. thanks Scott |
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#9 |
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MrExcel MVP
Join Date: Feb 2002
Location: Monterrey, Mexico
Posts: 1,433
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Scott,
I didn't know that your data was split up into separate columns for address, street, etc. This makes it a lot easier. Try the following: Sub NumbersFormat() For Each cell In Selection If IsNumeric(cell.Value) = False Or cell.Value = "" Then GoTo 1 If cell.Value = 11 Then cell.Value = "11th " ElseIf cell.Value = 12 Then cell.Value = "12th " ElseIf cell.Value = 13 Then cell.Value = "13th " ElseIf Right(cell.Value, 1) = 1 Then cell.Value = cell.Value & "st " ElseIf Right(cell.Value, 1) = 2 Then cell.Value = cell.Value & "nd " ElseIf Right(cell.Value, 1) = 3 Then cell.Value = cell.Value & "rd " Else: cell.Value = cell.Value & "th " End If 1 Next cell End Sub
__________________
Kind regards, Al Chara |
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#10 |
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New Member
Join Date: May 2002
Location: Broward Sheriffs Office
Posts: 3
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Thanks for your assistance sorry about the lack of direction. I have been experimenting myself with macros.
Let me show you. The issue is that numbers have to be assigned either a "th", "st", "rd", and "nd". The next issue is that the column consists of single digits (1-9), double digits (10-99), and triple digits (101-200). Here is the macro for single digit for "th" 'Replace numbers 4-5-6-7-8-9 (single digit) with 4th-5th-6th, etc Application.ReplaceFormat.NumberFormat = "0""th""" Selection.Replace What:="4", Replacement:="4", LookAt:=xlWhole, _ SearchOrder:=xlByColumns, MatchCase:=True, SearchFormat:=False, _ ReplaceFormat:=True Selection.Replace What:="5", Replacement:="5", LookAt:=xlWhole, _ SearchOrder:=xlByColumns, MatchCase:=True, SearchFormat:=False, _ ReplaceFormat:=True Selection.Replace What:="6", Replacement:="6", LookAt:=xlWhole, _ SearchOrder:=xlByColumns, MatchCase:=True, SearchFormat:=False, _ ReplaceFormat:=True Here is the macro for double digit ending in "th" 'Replace double digit numbers with "th"s (10-11-12-13-14-15-16-17-18-19-20 Application.ReplaceFormat.NumberFormat = "00""th""" Selection.Replace What:="10", Replacement:="10", LookAt:=xlWhole, _ SearchOrder:=xlByColumns, MatchCase:=True, SearchFormat:=False, _ ReplaceFormat:=True Selection.Replace What:="11", Replacement:="11", LookAt:=xlWhole, _ SearchOrder:=xlByColumns, MatchCase:=True, SearchFormat:=False, _ ReplaceFormat:=True So i am going to write the macro and test it and hopefully that will be the solution. I will post to let others know if it worked or not, so far i tested about 50 records and it seemed to work. Thanks for your input! Scott |
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