Hi and welcome to the forum.
Try something like this...
=0+DATEDIF(DATEVALUE("Jan 1, 2013"),TODAY(),"y")
Zero is the starting value if any
"Jan 1, 2013" is the "set" date
Substitute your start values and set date to suit. The formula, as it stands, should return a value of two
That worked! Thanks AlphaFrog. May I ratch it up a notch and ask if it's possible to include a 'start date' ie.
John Smith started work on 1 apr 2014 on salary point 40. he has a 9 month probation period which means he is not due an increment on 1 August 2014 but 1 August 2015 instead. How could this be incorporated in the above formula if, indeed, it can!