Check if cell contains a numeric character

nicolewh

Well-known Member
Joined
Aug 7, 2009
Messages
554
I want to check if a range("a1") contains a numeric character. Example:
if A1 = "asef45adsf" then answer is True
if A1 = adjsfaff" then answer is False

Thanks!
 
Last edited:

Excel Facts

Wildcard in VLOOKUP
Use =VLOOKUP("Apple*" to find apple, Apple, or applesauce

mikerickson

MrExcel MVP
Joined
Jan 15, 2007
Messages
24,207
=IF(SUMPRODUCT(COUNTIF(A1,"*"&{1,2,3,4,5,6,7,8,9,0}))>0, "Contains at least one numeric character, "not")
 

PA HS Teacher

Well-known Member
Joined
Jul 17, 2004
Messages
2,838

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how about

=SUMPRODUCT(--ISNUMBER(--MID($A$1,ROW($A:$A:INDEX($A:$A,LEN(A1))),1)))>0
 

Weaver

Well-known Member
Joined
Sep 10, 2008
Messages
5,196
one solution

=MIN(LEN(SUBSTITUTE(A1,MID("0123456789",ROW($A$1:$A$10),1),"")))<LEN(A1)

confirmed using ctrl+shift+enter (curly brackets appear {})
 

VoG

Legend
Joined
Jun 19, 2002
Messages
63,650

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Try this function

Code:
Function IsNum(r As Range) As Boolean
Dim i As Long
For i = 1 To Len(r.Value)
    If IsNumeric(Mid(r.Value, i, 1)) Then
        IsNum = True
        Exit For
    End If
Next i
End Function

then use e.g.

Code:
X=IsNum(Range("E5"))
 

Weaver

Well-known Member
Joined
Sep 10, 2008
Messages
5,196
4 different solutions - you gotta love this site!
 

Fowmy

Well-known Member
Joined
Jul 10, 2008
Messages
512
Office Version
  1. 365
Platform
  1. Windows
Yep, Let me add the 5th Solution for you

=COUNT(SEARCH({1,2,3,4,5,6,7,8,9,0},A1))>0
 
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