Comparing two columns

[Jeffrey Green]

This is escaping me . . . Columns A and B contain . . . for example . . .

<TABLE style="WIDTH: 112pt; BORDER-COLLAPSE: collapse" border=0 cellSpacing=0 cellPadding=0 width=149 x:str><COLGROUP><COL style="WIDTH: 64pt; mso-width-source: userset; mso-width-alt: 3108" width=85><COL style="WIDTH: 48pt" width=64><TBODY><TR style="HEIGHT: 12.75pt" height=17><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; WIDTH: 64pt; HEIGHT: 12.75pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8" height=17 width=85>apple</TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; WIDTH: 48pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8" width=64>Atlanta</TD></TR><TR style="HEIGHT: 12.75pt" height=17><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; HEIGHT: 12.75pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8" height=17>apple</TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8">Atlanta</TD></TR><TR style="HEIGHT: 12.75pt" height=17><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; HEIGHT: 12.75pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8" height=17>apple</TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8">NYC</TD></TR><TR style="HEIGHT: 12.75pt" height=17><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; HEIGHT: 12.75pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8" height=17>pear</TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8">Detroit</TD></TR><TR style="HEIGHT: 12.75pt" height=17><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; HEIGHT: 12.75pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8" height=17>pear</TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8">Detroit</TD></TR><TR style="HEIGHT: 12.75pt" height=17><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; HEIGHT: 12.75pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8" height=17>pear</TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8">Chicago</TD></TR><TR style="HEIGHT: 12.75pt" height=17><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; HEIGHT: 12.75pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8" height=17>banana</TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; BACKGROUND-COLOR: transparent; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8">Chicago</TD></TR></TBODY></TABLE>

What I want is unique pairs . . . so, If A1=A2 and B1=B2,1,0).

I ended up doing this the "poor man's way" and concatenated A and B then deleted dups, but wondering how to do it in 1 column . . . . thanks

 

[Sektor]

=if(and(a1=a2,b1=b2),1,0)

 

[Jeffrey Green]

Thank you . . . . . .