Correct Formulas for Mathematical Equations.

siash69

New Member
Joined
Nov 22, 2013
Messages
31
Could someone please check that my formulas are correct please.

y4m71nErILDgLpMGkCAJ2HFjer-qsgDNhbm4CipgCgHT7dnzCLkbyy5RoZDUWURIxD3QAlBAnujJWkf1XLR6mqNprzd7q2dirDDNmIhSsZMx9UerAHMu2-8VElokcszALcugcjMxWkINW6KDSc_-5JfMgndy93OLItsnGNUF_PXAfND5rFzxha-3CdG8WSqldW5axBgKqLAqBfNoCpIwLqRqw

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<v:shape id="_x0000_i1025" style="width: 52.5pt; height: 15pt;" type="#_x0000_t75">Thanks.


<v:imagedata o:title="" chromakey="white" src="file:///C:/Users/Ashburn/AppData/Local/Temp/msohtmlclip1/01/clip_image001.png">




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Excel Facts

Square and cube roots
The =SQRT(25) is a square root. For a cube root, use =125^(1/3). For a fourth root, use =625^(1/4).
The last two formulas seem OK to me. The first two ones, to the contrary, seem wrong - I attach my versions below.

J.Ty.
CellFormula
A1=(PI()*D1^2)/4
A2=0.25/(LOG10(K1/(3.7*D1)+5.74/(R1^0.9)))^2

<thead>
</thead><tbody>
</tbody>

<tbody>
</tbody>
 
Last edited:
Upvote 0
Almost every formula has errors, or they can simplified.

In the last two formulas, we cannot write "g", unless it is a named reference. But since G can be a column reference in some contexts, I suggest that you put the value of "g" into a cell.

It appears that "g" is the gravitational acceleration constant.

Suppose G1 is "g" for the proper units: either 9.80665 (m/s^2) or =980.665/(12*2.54) (ft/s^2). It is better to calculate the latter than to enter an approximate constant.

Assuming B5 is "D", C5 is "L", F5 is "K", G5 is "v" and H5 is "Re", and the following are to be calculated: A5 is "A", I5 is lambda, J5 is "hf" and K5 is "hl":

A5: =PI() * B5^2 / 4

I5: =0.25 / LOG10(F5/(3.7*B5) + 5.74/H5^0.9)^2

J5: =(I5 * C5/B5) * G5^2 / (2*$G$1)
or
J5: =I5 * C5 * G5^2 / (B5 * 2*$G$1)

K5: =F5 * G5^2 / (2*$G$1)
 
Last edited:
Upvote 0

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