Count consecutive cells above a certain value

Chrisscpu

New Member
Joined
Mar 14, 2016
Messages
6
I am trying to count the number of cells above a certain value in a table consecutively from right to left. I need it to stop counting if above 85%
.50.88.75.86.90
.50.90.70.75.80
.20.80.82.80
.84

<tbody>
</tbody>

So for the above table, the correct response (in a column F not pictured) would be:
0 (1st value is above 85%)
3 (4th value is above 85%)
5 (none are above 85%)

I have been trying to amend the following formula with a ctrl, shift enter:
={IFERROR(COLUMN(P2)-COLUMN(INDEX(D2:P2,,MATCH(9.99E+307,IF(D2:P2=0,1,"")))),0)}

Any help is greatly appreciated, and if the above formula is not feasible with this issue, that's fine. I'll take anything that works. I have a feeling I'm overlooking something pretty basic.
 

Excel Facts

How to total the visible cells?
From the first blank cell below a filtered data set, press Alt+=. Instead of SUM, you will get SUBTOTAL(9,)

MarcelBeug

Well-known Member
Joined
Apr 25, 2014
Messages
1,811
In F2, copy down:
Code:
=IFERROR(5-LOOKUP(2,1/($A2:$E2>0.85),COLUMN($A2:$E2)-COLUMN($A2)+1),5)
 

Chrisscpu

New Member
Joined
Mar 14, 2016
Messages
6
Thank you very much. I had to adapt to a larger sheet, so if anyone wants to see the variables, here is for a 13 column chart starting at D.

=IFERROR(13-LOOKUP(2,1/($D2:$P2>0.85),COLUMN($D2:$P2)-COLUMN($D2)+1),13)
 

MarcelBeug

Well-known Member
Joined
Apr 25, 2014
Messages
1,811
You're welcome. :cool:

I deliberately provided an adaptable formula with COLUMN($A2:$E2)-COLUMN($A2)+1 rather than {1, 2, 3, 4, 5}
 
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