Count consecutive cells above a certain value

[Chrisscpu]

I am trying to count the number of cells above a certain value in a table consecutively from right to left. I need it to stop counting if above 85%

.50	.88	.75	.86	.90
.50	.90	.70	.75	.80
.20	.80	.82	.80	.84

<tbody>
</tbody>

So for the above table, the correct response (in a column F not pictured) would be:
0 (1st value is above 85%)
3 (4th value is above 85%)
5 (none are above 85%)

I have been trying to amend the following formula with a ctrl, shift enter:
={IFERROR(COLUMN(P2)-COLUMN(INDEX(D2:P2,,MATCH(9.99E+307,IF(D2:P2=0,1,"")))),0)}

Any help is greatly appreciated, and if the above formula is not feasible with this issue, that's fine. I'll take anything that works. I have a feeling I'm overlooking something pretty basic.

 

[MarcelBeug]

In F2, copy down:

=IFERROR(5-LOOKUP(2,1/($A2:$E2>0.85),COLUMN($A2:$E2)-COLUMN($A2)+1),5)

 

[Chrisscpu]

Thank you very much. I had to adapt to a larger sheet, so if anyone wants to see the variables, here is for a 13 column chart starting at D.

=IFERROR(13-LOOKUP(2,1/($D2:$P2>0.85),COLUMN($D2:$P2)-COLUMN($D2)+1),13)

 

[MarcelBeug]

You're welcome.

I deliberately provided an adaptable formula with COLUMN($A2:$E2)-COLUMN($A2)+1 rather than {1, 2, 3, 4, 5}