Count without duplicates

[Nelson78]

Hello everybody.

I've a situation like the following:

column f column g
A ONE
A ONE
A TWO
A THREE
A THREE
B ONE
B ONE
B ONE
B TWO
A FOUR
A FOUR
A FOUR
A FOUR
A FIVE

I need a formula that counts how many differents values in column g for the value A in column f (in the example 5) and how many different values in column g for the value B in column f (in the example 2).

Thank you.

 

[Marcelo Branco]

Try

	F​	G​	H​	I​	J​
1​					CountUnique​
2​	A​	ONE​		A​	5​
3​	A​	ONE​		B​	2​
4​	A​	TWO​
5​	A​	THREE​
6​	A​	THREE​
7​	B​	ONE​
8​	B​	ONE​
9​	B​	ONE​
10​	B​	TWO​
11​	A​	FOUR​
12​	A​	FOUR​
13​	A​	FOUR​
14​	A​	FOUR​
15​	A​	FIVE​

Array formula in J2 copied down
=SUM(IF(FREQUENCY(IF(F$2:F$15=I2,MATCH(G$2:G$15,G$2:G$15,0)),ROW(G$2:G$15)-ROW(G$2)+1),1))
confirmed with Ctrl+Shift+Enter, not just Enter

M.

 

[Nelson78]

Many thanks for the support: it works perfectly well.

Just add a constraint, if possible: to exclude the rows with value 0 in column h

column f column g column h
A ONE 7
A ONE 5
A TWO 0
A THREE 4
A THREE 2
B ONE 3
B ONE 0
B ONE 5
B TWO 6
A FOUR 0
A FOUR 2
A FOUR 4
A FOUR 3
A FIVE 2

 

[Marcelo Branco]

Maybe...

	F​	G​	H​	I​	J​	K​
1​						CountUnique​
2​	A​	ONE​	7​		A​	4​
3​	A​	ONE​	5​		B​	2​
4​	A​	TWO​	0​
5​	A​	THREE​	4​
6​	A​	THREE​	2​
7​	B​	ONE​	3​
8​	B​	ONE​	0​
9​	B​	ONE​	5​
10​	B​	TWO​	6​
11​	A​	FOUR​	0​
12​	A​	FOUR​	2​
13​	A​	FOUR​	4​
14​	A​	FOUR​	3​
15​	A​	FIVE​	2​

Array formula in K2
=SUM(IF(FREQUENCY(IF(F$2:F$15=J2,IF(H$2:H$15<>0,MATCH(G$2:G$15,G$2:G$15,0))),ROW(G$2:G$15)-ROW(G$2)+1),1))
Ctrl+Shift+Enter

M.

 

[Nelson78]

Maybe...

	F​	G​	H​	I​	J​	K​
1​						CountUnique​
2​	A​	ONE​	7​		A​	4​
3​	A​	ONE​	5​		B​	2​
4​	A​	TWO​	0​
5​	A​	THREE​	4​
6​	A​	THREE​	2​
7​	B​	ONE​	3​
8​	B​	ONE​	0​
9​	B​	ONE​	5​
10​	B​	TWO​	6​
11​	A​	FOUR​	0​
12​	A​	FOUR​	2​
13​	A​	FOUR​	4​
14​	A​	FOUR​	3​
15​	A​	FIVE​	2​

Array formula in K2
=SUM(IF(FREQUENCY(IF(F$2:F$15=J2,IF(H$2:H$15<>0,MATCH(G$2:G$15,G$2:G$15,0))),ROW(G$2:G$15)-ROW(G$2)+1),1))
Ctrl+Shift+Enter

M.

Thank's: until today, it seems ok.

Now, I'm going to study the structure of the formula.