DISTINCTCOUNTCOLUMNVISIBLECELLS

=DISTINCTCOUNTCOLUMNVISIBLECELLS(ColumnVector)

ColumnVector
Required.

Count the visible unique elements in a ColumnVector, regardless of their frequencies. Works only on a ColumnVector.

GeertD

Board Regular
Joined
Dec 22, 2020
Messages
60
Office Version
  1. 365
Platform
  1. Windows
DISTINCTCOUNTCOLUMNVISIBLECELLS: Count the visible unique elements in a ColumnVector, regardless of their frequencies. Works only on a ColumnVector.
This one is not so trivial. IMO "DistinctCount" should be just another function in the toolbox of the SUBTOTAL function.
Excel Formula:
=LAMBDA(Source,LET(
   IndexFromZero,SEQUENCE(ROWS(Source),,0),
   IsVisible,SUBTOTAL(103,OFFSET(Source,IndexFromZero,0,1)),
   VisibleSourceData,IF(IsVisible,Source,""),
   COUNTA(UNIQUE(VisibleSourceData))-(1-PRODUCT(IsVisible))
))
DXLR's LAMBDA.LET Library_v00.07.xlsb
ABCDEFGHIJ
1Filtered Table:
2First NameLast NameScoreCountryCountRows:20
3AliceLivingstone6GermanyDistinctCount:14(First Name)
4MikaylaLindberg14GermanyDistinctCountColumnVisibleCells:4(First Name)
7MylaStukeby5Germany
9MikaylaSlater14Mexico
11AliceJohansen34MexicoDistinctCount:16(Score)
12KarlTilton11MexicoDistinctCountColumnVisibleCells:6(Score)
21KarlIngoldsby13Germany
23
24Unfiltered Table:
25First NameLast NameScoreCountry
26AliceLivingstone6Germany
27MikaylaLindberg14Germany
28CharlesHurst3Poland
29LondonEdmund1Argentina
30MylaStukeby5Germany
31XzavierAngus4Romania
32MikaylaSlater14Mexico
33AlicePoole4Finland
34AliceJohansen34Mexico
35KarlTilton11Mexico
36MikaylaBruno18Finland
37PaxtonChadsey3USA
38LamontLacy17Slovakia
39JaylanForbes9Egypt
40PaxtonBeckley15Brazil
41AlejandraDonoso22Spain
42DeonteAstley13Thailand
43AlfredSarisbury27Argentina
44KarlIngoldsby13Germany
45RylanHasbrouck33Indonesia
46
Sandbox_Mr.Excel
Cell Formulas
RangeFormula
H2H2=COUNTA(tblTop[First Name])
H3H3=DistinctCount(tblTop[First Name])
H4H4=DistinctCountColumnVisibleCells(tblTop[First Name])
H11H11=DistinctCount(tblTop[Score])
H12H12=DistinctCountColumnVisibleCells(tblTop[Score])
 
Upvote 0
Here's a better formula (note to Old School thinking me: if you have the filter mask, just use it in FILTER):
Excel Formula:
DistinctCountVisibleCells(ColumnVector)
=LAMBDA(Source,LET(
   RowdexFromZero,SEQUENCE(ROWS(Source),,0),
   IsVisible,SUBTOTAL(103,OFFSET(Source,RowdexFromZero,0,1)),
   COUNTA(UNIQUE(FILTER(Source,IsVisible)))
))
(ColumnVector)
(I dropped the "COLUMN" from the name)

Note: all formulas can be mashed together since there is no argument repeat, but I left it like this for clarity and educational puposes.
 
Totally rad, Geert!!!!!Here is non-lambda:
=ROWS(UNIQUE(FILTER(fSales[SalesRep],SUBTOTAL(3,OFFSET(fSales[[#Headers],[SalesRep]],SEQUENCE(ROWS(fSales[SalesRep])),)))))
Same things but less elegant ; )P.S. It is so funny, Mr Excel posted video yesterday and I could not figure out a single cell formula. But this morning during breakfast, it came to me: Boom! So funny how the creative process works.
 
Totally rad, Geert!!!!!Here is non-lambda:
=ROWS(UNIQUE(FILTER(fSales[SalesRep],SUBTOTAL(3,OFFSET(fSales[[#Headers],[SalesRep]],SEQUENCE(ROWS(fSales[SalesRep])),)))))
Same things but less elegant ; )P.S. It is so funny, Mr Excel posted video yesterday and I could not figure out a single cell formula. But this morning during breakfast, it came to me: Boom! So funny how the creative process works.
Well, Mike, how about that?!
You used the ROWS function in the calculation. That is even beter!
Here's why I find that:
  1. The ROWS function is the equivalent to the COUNTROWS function in DAX (and it also counts blank rows!).
    And whenever the similarities between the various environments can be emphasized, I will choose to do so. Helps with the transition between them.
  2. And it also counts blank rows! Making your solution more versatile and more robust than mine.
Thanks, I will adapt, or rather: adopt, in this case. :)

But wait, there's more: there is one thing I don't understand about your solution:
  • You replaced the oh so important arguments "0,1" by "," (just a comma):
    • in the Excel grid that works –I verified myself, too–,
    • but inside of the LET function it doesn't – the "0,1" is crucial (as per my earlier experience and as I explained in my video).
  • any idea as to why this behavior is different?
 
I have no idea why that does not work in LET!?!?!
The "just a comma" in OFFSET columns will default to zero if left empty. The last two arguments in OFFSET assume the dimensions of the first argument if left out.
But I have no idea why it does not work in LET. Anytime the behavior of a function, especially an old standby like OFFSET does not work the same in a new function, that is worrisome... : (
 
I have no idea why that does not work in LET!?!?!
The "just a comma" in OFFSET columns will default to zero if left empty. The last two arguments in OFFSET assume the dimensions of the first argument if left out.
But I have no idea why it does not work in LET. Anytime the behavior of a function, especially an old standby like OFFSET does not work the same in a new function, that is worrisome... : (
Hold on, the starting position of your ColumnVector is different from mine: You start from the header, and therefore need a RowdexFromOne, whereas I start from the upper-left position in the ColumnVector itself (that's what it takes if you put in an entire array instead of a single cell), and therefore I need a RowdexFromZero.
So, in case of my formula the other arguments cannot default to equal zero or (the first element in the vector of) the first argument.
I could differentiate the starting position from the vector itself, but that would introduce an extra argument to input to the function. I see you did exactly that:
  • Your starting position: fSales[[#Headers],[SalesRep]]
  • Your Vector: fSales[SalesRep]
I tested this and indeed that way it works in the LAMBDA.LET-environment, as well, with just the comma – so there is nothing to worry about. :)

But I'm not going to follow that line of thought, because I feel that adding the need for an additional argument (or conversely: adding more computational complexity [another offset?]) just to be able to use that "just a comma"-trick is a step in the wrong direction, in terms of enduser-friendliness / intuitive use of the function. Please don't take offence.
The way I made the function right now, you use it just the same way as you would any other aggregator function on a column (like SUM, etc.).

Conclusion: everything is predictable and works the same way both in the Excel Grid and in a LAMBDA.LET-environment. :)
 

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