Extract 7 digit number from text

Jackadair

New Member
Joined
Sep 22, 2022
Messages
3
Office Version
  1. 365
Evening!

First post, mostly be back in the future if this gets answered!

Need to extract 7 digit number from text

Example

Abbb bbb b 1234567 (os3)(n)
Is so3 bb | 7654321 (33pp)
So3 bea | 1111111(or8)

Need a formula that would extract the 7 digit number from all those text at once so it would look like

1234567
7654321
1111111
 
I don't see the difference between the output of my formula in post#4 and yours in this regard.
I wasn't suggesting there was a difference. I was attempting to re-emphasising the point (that you had already made) to the OP in case it was an issue for them.
 
Upvote 0

Excel Facts

Will the fill handle fill 1, 2, 3?
Yes! Type 1 in a cell. Hold down Ctrl while you drag the fill handle.
Without knowing what might really be in the data, I would say that posts 5 & 6 suggestions are not robust. Examples of incorrect results:

22 09 23.xlsm
AB
1A12561E2 Abbb 1234567 (os3)1256100
2A12DEC22 Abbb 1234567 (os3)44907
Extract (2)
Cell Formulas
RangeFormula
B1B1=AGGREGATE(14,6,MID(A1,ROW(INDIRECT("1:" & LEN(A1))),7)+0,1)
B2B2=INDEX(SORT(MID(SUBSTITUTE(A2," ",""),SEQUENCE(,LEN(A2)),7)+0,,,1),1)


Assuming numbers longer than 7 digits are not possible, I would suggest some minor tweaks to the post 4 formula.
The double quotes in REPT can be omitted
The addition near the end can be avoided by using zero instead of 1
The two blank arguments in TEXTJOIN can be avoided by using CONCAT instead

22 09 23.xlsm
AB
1Abbb bbb b 1234567 (os3)1234567
2Is so3 bb | 7654321 (33pp)7654321
3So3 bea | 1111111(or8)1111111
4A12561E2 Abbb 1234567 (os3)1234567
5A12DEC22 Abbb 1234567 (os3)1234567
Extract
Cell Formulas
RangeFormula
B1:B5B1=MID(A1,SEARCH(REPT(0,7),CONCAT(IFERROR(MID(A1,SEQUENCE(LEN(A1)),1)*0,2))),7)
Looks brilliant.

I've try adding this formula into excel, litteraly copy and paste into A2 cell ( all my data is in A1)

Not really getting a result, any assistance?

Really appreciate your help!
 
Upvote 0
@Peter_SSs
My second formula passes all of your tests with the following adjustment (2 characters longer than your adjustment to post #4's formula):
b.xlsb
AB
1Abbb bbb b 1234567 (os3)1234567
2Is so3 bb | 7654321 (33pp)7654321
3So3 bea | 1111111(or8)1111111
4A12561E2 Abbb 1234567 (os3)1234567
5A12DEC22 Abbb 1234567 (os3)1234567
Sheet2 (2)
Cell Formulas
RangeFormula
B1:B5B1=INDEX(SORT(TEXT(MID(SUBSTITUTE(A1," ",""),SEQUENCE(,LEN(A1)),7)+0,"#"),,,1),1)
 
Upvote 0
all my data is in A1
Do you mean like this?

22 09 23.xlsm
A
1Abbb bbb b 1234567 (os3)(n) Is so3 bb | 7654321 (33pp) So3 bea | 1111111(or8)
Extract (3)


My second formula passes all of your tests with the following adjustment ..
I assume that you are addressing me? What about this?

22 09 23.xlsm
AB
1A1 2 2 3 1 1 2 2 Abbb 1234567 (os3)1223112
Extract (2)
Cell Formulas
RangeFormula
B1B1=INDEX(SORT(TEXT(MID(SUBSTITUTE(A1," ",""),SEQUENCE(,LEN(A1)),7)+0,"#"),,,1),1)
 
Upvote 0
I assume that you are addressing me? What about this?

22 09 23.xlsm
AB
1A1 2 2 3 1 1 2 2 Abbb 1234567 (os3)1223112
Extract (2)
Cell Formulas
RangeFormula
B1B1=INDEX(SORT(TEXT(MID(SUBSTITUTE(A1," ",""),SEQUENCE(,LEN(A1)),7)+0,"#"),,,1),1)
Ah, you're good. Here's the obvious fix (no change in length):
b.xlsb
AB
1Abbb bbb b 1234567 (os3)1234567
2Is so3 bb | 7654321 (33pp)7654321
3So3 bea | 1111111(or8)1111111
4A12561E2 Abbb 1234567 (os3)1234567
5A12DEC22 Abbb 1234567 (os3)1234567
6A1 2 2 3 1 1 2 2 Abbb 1234567 (os3)1234567
Sheet2 (2)
Cell Formulas
RangeFormula
B1:B6B1=INDEX(SORT(TEXT(MID(SUBSTITUTE(A1," ","|"),SEQUENCE(,LEN(A1)),7)+0,"#"),,,1),1)
 
Upvote 0
Here's the obvious fix (no change in length):
In my experience, any attempt to deal with such a 'number string' other than character-by-character is fraught with risk. Why not stick to the earlier one that works?

What about?

22 09 23.xlsm
AB
1A1111.11 Abbb 1234567 (os3)1111
Extract (2)
Cell Formulas
RangeFormula
B1B1=INDEX(SORT(TEXT(MID(SUBSTITUTE(A1," ","|"),SEQUENCE(,LEN(A1)),7)+0,"#"),,,1),1)
 
Upvote 0

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