Extract IP Address from text/string

Snypa

New Member
Joined
Nov 1, 2013
Messages
45
Hello,

I have a vlookup that will return values such as the following:

1. "123.123.123.xxx"
2. "123.32.32.89 (VPN)"
3. "123.32.32.89 RT"
4. "123.32.32.89 VPN"
5. "D 123.32.32.xxx S 123.32.123.xxx"

I currently have the following formula which only works in the first instance: =LEFT(C7,FIND(".",C7,FIND(".",C7,FIND(".",C7)+1)+1)-1)&".220"

What I need is a formula that will extract either the whole IP address in instances 2, 3, 4 or the first 3 octets in the final instance that would also work in the first instance (only need the first IP address).
 

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Is this what you want?

Excel 2010
CD
7123.123.123.xxx123.123.123.220
8123.32.32.89 (VPN)123.32.32.220
9123.32.32.89 RT123.32.32.220
10123.32.32.89 VPN123.32.32.220
11D 123.32.32.xxx S 123.32.123.xxx123.32.32.220
Sheet1
Cell Formulas
RangeFormula
D7=MID(C7,SEARCH(".",C7)-3,SEARCH(".",C7,SEARCH(".",C7,SEARCH(".",C7)+1)+1)-(SEARCH(".",C7)-3-1))&"220"
D8=MID(C8,SEARCH(".",C8)-3,SEARCH(".",C8,SEARCH(".",C8,SEARCH(".",C8)+1)+1)-(SEARCH(".",C8)-3-1))&"220"
D9=MID(C9,SEARCH(".",C9)-3,SEARCH(".",C9,SEARCH(".",C9,SEARCH(".",C9)+1)+1)-(SEARCH(".",C9)-3-1))&"220"
D10=MID(C10,SEARCH(".",C10)-3,SEARCH(".",C10,SEARCH(".",C10,SEARCH(".",C10)+1)+1)-(SEARCH(".",C10)-3-1))&"220"
D11=MID(C11,SEARCH(".",C11)-3,SEARCH(".",C11,SEARCH(".",C11,SEARCH(".",C11)+1)+1)-(SEARCH(".",C11)-3-1))&"220"
 
Upvote 0
This is great! Thanks.

Just one issue, the formula replaces the forth octet with 220, however, the ones without 'xxx' don't need it replacing. could you change those? (row 8-10)

Is this what you want?
Excel 2010
CD
7123.123.123.xxx123.123.123.220
8123.32.32.89 (VPN)123.32.32.220
9123.32.32.89 RT123.32.32.220
10123.32.32.89 VPN123.32.32.220
11D 123.32.32.xxx S 123.32.123.xxx123.32.32.220

<colgroup><col><col><col></colgroup><thead>
</thead><tbody>
</tbody>
Sheet1

Worksheet Formulas
CellFormula
D7=MID(C7,SEARCH(".",C7)-3,SEARCH(".",C7,SEARCH(".",C7,SEARCH(".",C7)+1)+1)-(SEARCH(".",C7)-3-1))&"220"
D8=MID(C8,SEARCH(".",C8)-3,SEARCH(".",C8,SEARCH(".",C8,SEARCH(".",C8)+1)+1)-(SEARCH(".",C8)-3-1))&"220"
D9=MID(C9,SEARCH(".",C9)-3,SEARCH(".",C9,SEARCH(".",C9,SEARCH(".",C9)+1)+1)-(SEARCH(".",C9)-3-1))&"220"
D10=MID(C10,SEARCH(".",C10)-3,SEARCH(".",C10,SEARCH(".",C10,SEARCH(".",C10)+1)+1)-(SEARCH(".",C10)-3-1))&"220"
D11=MID(C11,SEARCH(".",C11)-3,SEARCH(".",C11,SEARCH(".",C11,SEARCH(".",C11)+1)+1)-(SEARCH(".",C11)-3-1))&"220"

<thead>
</thead><tbody>
</tbody>

<tbody>
</tbody>
 
Upvote 0
So the row 8-10 do not need 220 added?


Excel 2010
CD
7123.123.123.xxx123.123.123.220
8123.32.32.89 (VPN)123.32.32.89
9123.32.32.89 RT123.32.32.89
10123.32.32.89 VPN123.32.32.89
11D 123.32.32.xxx S 123.32.123.xxx123.32.32.220
Sheet5
Cell Formulas
RangeFormula
D7=MID(C7,SEARCH(".",C7)-3,SEARCH(".",C7,SEARCH(".",C7,SEARCH(".",C7)+1)+1)-(SEARCH(".",C7)-3-1))&IF(H7="x","220",MID(C7,G7+1,2))
D8=MID(C8,SEARCH(".",C8)-3,SEARCH(".",C8,SEARCH(".",C8,SEARCH(".",C8)+1)+1)-(SEARCH(".",C8)-3-1))&IF(H8="x","220",MID(C8,G8+1,2))
D9=MID(C9,SEARCH(".",C9)-3,SEARCH(".",C9,SEARCH(".",C9,SEARCH(".",C9)+1)+1)-(SEARCH(".",C9)-3-1))&IF(H9="x","220",MID(C9,G9+1,2))
D10=MID(C10,SEARCH(".",C10)-3,SEARCH(".",C10,SEARCH(".",C10,SEARCH(".",C10)+1)+1)-(SEARCH(".",C10)-3-1))&IF(H10="x","220",MID(C10,G10+1,2))
D11=MID(C11,SEARCH(".",C11)-3,SEARCH(".",C11,SEARCH(".",C11,SEARCH(".",C11)+1)+1)-(SEARCH(".",C11)-3-1))&IF(H11="x","220",MID(C11,G11+1,2))
 
Upvote 0
Hello,

Thanks again for the reply, the first formula does not seem to work. Additionally, it has references to column H and G, is this correct? I changed it all to column C and I got a value error.

Please help :)
 
Upvote 0
Hi,

I think it might be a lot easier for us to help if you show various samples and expected results.
 
Upvote 0
These samples and expected output are correct but the formula does not seem to product them, perhaps a mistype somewhere?

So the row 8-10 do not need 220 added?

Excel 2010
CD
7123.123.123.xxx123.123.123.220
8123.32.32.89 (VPN)123.32.32.89
9123.32.32.89 RT123.32.32.89
10123.32.32.89 VPN123.32.32.89
11D 123.32.32.xxx S 123.32.123.xxx123.32.32.220

<colgroup><col><col><col></colgroup><thead>
</thead><tbody>
</tbody>
Sheet5

Worksheet Formulas
CellFormula
D7=MID(C7,SEARCH(".",C7)-3,SEARCH(".",C7,SEARCH(".",C7,SEARCH(".",C7)+1)+1)-(SEARCH(".",C7)-3-1))&IF(H7="x","220",MID(C7,G7+1,2))
D8=MID(C8,SEARCH(".",C8)-3,SEARCH(".",C8,SEARCH(".",C8,SEARCH(".",C8)+1)+1)-(SEARCH(".",C8)-3-1))&IF(H8="x","220",MID(C8,G8+1,2))
D9=MID(C9,SEARCH(".",C9)-3,SEARCH(".",C9,SEARCH(".",C9,SEARCH(".",C9)+1)+1)-(SEARCH(".",C9)-3-1))&IF(H9="x","220",MID(C9,G9+1,2))
D10=MID(C10,SEARCH(".",C10)-3,SEARCH(".",C10,SEARCH(".",C10,SEARCH(".",C10)+1)+1)-(SEARCH(".",C10)-3-1))&IF(H10="x","220",MID(C10,G10+1,2))
D11=MID(C11,SEARCH(".",C11)-3,SEARCH(".",C11,SEARCH(".",C11,SEARCH(".",C11)+1)+1)-(SEARCH(".",C11)-3-1))&IF(H11="x","220",MID(C11,G11+1,2))

<thead>
</thead><tbody>
</tbody>

<tbody>
</tbody>
 
Upvote 0
I'm wishing you would show "more samples with Results" instead of us trying to guess what you need, so without that, see if this works for you:


Book1
ABC
1123.123.123.xxx123.123.123.220
2123.32.32.89 (VPN)123.32.32.89
3123.32.32.89 RT123.32.32.89
4123.32.32.89 VPN123.32.32.89
5D 123.32.32.xxx S 123.32.123.xxx123.32.32.220
Sheet33
Cell Formulas
RangeFormula
C1=TRIM(LEFT(SUBSTITUTE(SUBSTITUTE(MID(A1,FIND(".",A1)-3,255),"xxx",220)," ",REPT(" ",100)),100))


C1 formula copied down.
 
Upvote 0
That works when I test it on a new worksheet but when I use it within my Spread sheet, I am getting a #Value error. Any idea why, such a number or text format?

Looking at the error its the mid statement that gives the error. It looks correct though:

mid("10.88.25.xxx", 0, 255)
 
Last edited:
Upvote 0

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