Extrapolation Method

BJW75

New Member
Joined
Feb 18, 2020
Messages
4
Office Version
  1. 2016
Platform
  1. Windows
I inherited some reports where we are calculating lost yield. We currently use a formula converting the minutes of sampling into the hours worked as a percent. The weight found as a loss is then summed for the shift and then divided by this percent. This does not seem correct, but I am having trouble finding a better method, as we do not have a theoretical loss to calculate yield loss based on theoretical to experimental findings.

Any ideas?
 

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Welcome to the Board!

Any ideas
Possibly. But your question is pretty vague/generic.
I think you may have better look if you could post an example for us, along with some expected results regarding what you are looking for.
 
Upvote 0
Thank you. I have included the formulas and table sample format below for better explanation.
Hours worked per day
10​
0.83% ‘% inspct
=MIN /(HRS*60)
Total Min of Waste Insp
5​
Waste
Sums of QC data​
Calculated Tonnage​
Widgets <1”​
23.90​
55.00​
Waste widgets​
13.86​
27.00​
Machining xs scrap​
3.36​
15.00​
Burrs/gores scrap​
3.67​
5.00​
Inspections Total​
44.78​
102.00​
Day​
6447.96 =IFERROR(total/ % inspected)​
14,688.00 =IFERROR(total tonnage/ % inspected)​
 
Upvote 0
Sorry, I have been away for a while, and just getting back now.

Not sure if I am the best person to help with this. But I am curious. I am looking at your chart, and I am not too sure what I am looking at, or at least how it relates to your problem.
You might need to explain how it all ties in to your problem, and what hope/expect to get out of it.
Maybe someone who has some experience in this arena will see it and be able to provide some suggestions.
 
Upvote 0

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