F10*(F13>0.01), is this a valid formula?

Happyking

Board Regular
Joined
Jul 1, 2006
Messages
204
I'm looking at a model and it has a formula I don't understand.

F10*(F13>0.01)
the input for F13 is "no"

So what does F13>0.01 return?

Thanks! :rolleyes:
 

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What did Pito Salas invent?
Pito Salas, working for Lotus, popularized what would become to be pivot tables. It was released as Lotus Improv in 1989.

Oaktree

MrExcel MVP
Joined
Jun 20, 2002
Messages
8,010
Office Version
  1. 365
If F13 = "no", then F13>0.01 returns TRUE. In fact, any string would be considered greater than any number.

So, your formula is =F10*TRUE. Since TRUE is calculated as a 1 and FALSE is calculated as a 0, your formula =F10*("no">0.01) will return =F10*1, or just F10.

If F13 has a value, then your formula =F10*(F13>0.01) will either return 0(if F13 <= 0.01) or F10 (if F13 > 0.01).
 

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