Find Rows that have a different value

lmoran89

New Member
Joined
Apr 9, 2019
Messages
12
Office Version
  1. 2013
Platform
  1. Windows
This sounds like it should be simple, but I am struggling. Thank you in advance

I have 2 columns of data similar to the below (but 44,000 rows). First column is an account number, second is an identifier. I need to identify the where an account number has both a 2 and 1.

2122102
2122102
2122102
2122102
2122101
2122101
2122101
2122101

<colgroup><col><col></colgroup><tbody>
</tbody>
 

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Welcome to the board.

Yeah, this is an ugly formula, for sure. Interesting problem, though. Assuming your Account values start at A1, then:
=IFERROR( IF( AND( FIND( "1", A1), FIND( "2", A1)), "both", "?"), IFERROR( IF( FIND( "1", A1), "1", "??"), IFERROR( IF( FIND( "2", A1), "2", "???"), "neither")))
 
Last edited:
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Welcome to the Board!

All things being equal, I think this is something that is probably easier accomplished in Microsoft Access, through a "Grouped" and a "Totals" Query. Access may handle that amount of data a little more efficiently too.
However, I realize that you may not have access to Access. If you do, though, let me know, and I can probably help you get what you need.
 
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Joe4 - Agreed this is something that should be in Access. I had already loaded it, but your help is appreciated
 
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Let's say the table named is "Table1" and the field names are "AccountNumber" and "Identifier", and the possible value for Identifier are the numeric values 1 and 2.
Then, go to Query Design, change to SQL View, and paste this query code in:
Code:
SELECT AccountNumber
FROM Table1
GROUP BY AccountNumber
HAVING (Sum(IIf([Identifier]=1,1,0))>0) AND (Sum(IIf([Identifier]=2,1,0))>0);
This should return all AccountNumbers who have both 1 and 2.
 
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Thank you. I'm getting the "Enter Parameter Value" on the Identifier field though. The field was initially text, but changed the data type to number, but still getting that message
 
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Whenever you see that, and you didn't set a parameter, it typically means you have a typo in the field name (in this case, the field name you are using in the query here does not exactly match the field name in the table).
 
Last edited:
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You are welcome.
 
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