Finding All First of Sequence in a Table

Innoguide

Board Regular
Joined
Sep 13, 2011
Messages
159
I have a table of dates (column B) associated with event Identifiers (Column A) and need a formula in column C that will find the first date for each event as shown in the table below.

I've been playing with Index-Match and know that if the row is the min of all the rows where the event is the same as that row, then the result should be "First" otherwise "" but am struggling to get the correct formula
Here is what I was trying but am missing something
=IF(b2=MIN(INDEX(b$2:b$15,MATCH(a2,a$2:a$15))),"First","")

Any suggestions for a formula would be greatly appreciated

ABC
1EventDateFirst in Sequence
2F1-1231/2/2019
3F1-1231/7/2019
4F1-1231/7/2019
5F1-1231/1/2019
6F7-1252/1/2019
7F7-1252/5/2019
8F7-1252/7/2019
9F7-1251/15/2019First
10F7-1252/1/2019
11R2-1234453/1/2019First
12R2-1234453/15/2019
13R2-1234453/12/2019
14F7-1253/15/2019
15F1-12312/25/2018First

<tbody>
</tbody>
 
Last edited:

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Marcelo Branco

MrExcel MVP
Joined
Aug 23, 2010
Messages
16,393
Array formula in C2 copied down
=IF(B2=MIN(IF(A$2:A$15=A2,B$2:B$15)),"First","")
confirmed with Ctrl+Shift+Enter, not just Enter

M.
 

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