Finding cell value of first non-blank cell in a range

G00DNESS

Board Regular
Joined
Aug 6, 2014
Messages
60
Using Excel 2003, in Cell CZ32, I am trying to use a formula that will return the value of the first non blank cell in CM32:CY32. CM32:CY32 contain formulas. I will need to use this formula separately for rows 32--58. I'm using the following, but if the cells within the range are all blank it returns errors.

1.
=(INDEX(CM32:CY32,MATCH(TRUE,CM32:CY32<>"",0)))
(and CTRL+SHIFT+ENTER)
Returns: Error #N/A

2.
=IFERROR(INDEX(CM32:CY32,MATCH(TRUE,CM32:CY32<>"",0)),"")
(and CTRL+SHIFT+ENTER)
Returns: Error #NAME?

Any help with this is much appreciated.
 

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What is =ROMAN(40) in Excel?
The Roman numeral for 40 is XL. Bill "MrExcel" Jelen's 40th book was called MrExcel XL.
IFERROR was introduced w/Excel2007 - so Excel 2003 doesn't recognize the name of that function. Try:
Rich (BB code):
=IF(ISERROR(INDEX(CM32:CY32,MATCH(TRUE,CM32:CY32<>"",0))),"",INDEX(CM32:CY32,MATCH(TRUE,CM32:CY32<>"",0)))

 
Upvote 0
IFERROR was introduced w/Excel2007 - so Excel 2003 doesn't recognize the name of that function. Try:
Rich (BB code):
=IF(ISERROR(INDEX(CM32:CY32,MATCH(TRUE,CM32:CY32<>"",0))),"",INDEX(CM32:CY32,MATCH(TRUE,CM32:CY32<>"",0)))

Thank you so much Joe! It worked quite well.
 
Upvote 0
Also, it might be of interest:

If a text-valued range:
Rich (BB code):
=IF(COUNTIF(CM32:CY32,"?*"),INDEX(CM32:CY32,MATCH(TRUE,CM32:CY32<>"",0)),"")
If a numeric range:
Rich (BB code):
=IF(COUNT(CM32:CY32),INDEX(CM32:CY32,MATCH(TRUE,CM32:CY32<>"",0)),"")
Otherwise:
Rich (BB code):
=IF(COUNTIF(CM32:CY32,"?*")+COUNT(CM32:CY32),
  INDEX(CM32:CY32,MATCH(TRUE,CM32:CY32<>"",0)),"")
 
Upvote 0

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