Finding Last Empty Cell In A Dynamic Range

Ark68

Well-known Member
Joined
Mar 23, 2004
Messages
3,860
Office Version
  1. 365
  2. 2016
Platform
  1. Windows
I'm struggling with a relatively easy function in vba. I am trying to find the row number based on the first empty cell in a dynamic range (rng_cntb)
Here is what I have that isn't providing the right answer:

Code:
Set rng_cntb = ws_master.Range("A13:A" & mstr_lr_pdr)
ws_master.Unprotect
x = rng_cntb.SpecialCells(xlCellTypeLastCell).Row
msgbox "Next available empty row in the available range is: " & x

In my testing, mstr_lr_pdr = 36, so therefore rng_cntb = ws_master.range("A13:A36")
The last cell in that range is at A21.
I am expecting a value for x of 22, but I'm getting 77.

Can someone correct my code, or suggest an alternate. I know how to find the last row in an entire worksheet, but not within a defined range.
 

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MARK858

MrExcel MVP
Joined
Nov 12, 2010
Messages
14,001
Office Version
  1. 365
  2. 2010
Platform
  1. Windows
  2. Mobile
Maybe the below if you mean the next empty cell after the last cell with data

VBA Code:
Set rng_cntb = ws_master.Range("A13:A" & mstr_lr_pdr)
ws_master.Unprotect
x = rng_cntb.Find("*", , xlValues, , xlByRows, xlPrevious).Row + 1
MsgBox "Next available empty row in the available range is: " & x
 
Solution

Ark68

Well-known Member
Joined
Mar 23, 2004
Messages
3,860
Office Version
  1. 365
  2. 2016
Platform
  1. Windows
Thank you Mark! That did the trick.
 

MARK858

MrExcel MVP
Joined
Nov 12, 2010
Messages
14,001
Office Version
  1. 365
  2. 2010
Platform
  1. Windows
  2. Mobile
You're welcome
 

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