Formula that creates a unique number for repeating list numbers

goldiekratz437

New Member
Joined
May 14, 2013
Messages
9
Hi Mr. Excel Whiz Kids:

I need a formula that will add .1, .2, .3, etc. to a repeating list number. See the example below.
Project Work Id</SPAN>
8069000</SPAN>
8069000</SPAN>
8069000</SPAN>
8069000.1</SPAN>
8168000</SPAN>
8168000</SPAN>
8169000</SPAN>
8169000</SPAN>
9034000</SPAN>
9034000</SPAN>
9034000</SPAN>
9034000.1</SPAN>
10000948</SPAN>
10000948</SPAN>
10000948</SPAN>
10000948.1</SPAN>
10000948</SPAN>
10000948.2</SPAN>

<TBODY>
</TBODY>


Thank you so much. You guys/gals are great!

Jeanette
 

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If your ID's is in column A starting in cell A2
Copy this formula to cell B2

=IF(COUNTIF(A$2:A2,A2)>1,A2&"."&COUNTIF(A$2:A2,A2)-1,A2)

Copy the formula down
 
Upvote 0
are the numbers always going to be in order

I think this will work -

=IF( (A2=A1), B1+0.1,A2)

Excel Workbook
AB
280690008069000
380690008069000.1
481680008168000
581690008169000
690340009034000
790340009034000.1
81000094810000948
91000094810000948.1
101000094810000948.2
Sheet1
 
Upvote 0
80690008069000.0=A1
80690008069000.1=IF(COUNTIF($A$1:A2,A2)>1,A2+COUNTIF($A$1:A2,A2)*0.1-0.1,A2)
81680008168000.0=IF(COUNTIF($A$1:A3,A3)>1,A3+COUNTIF($A$1:A3,A3)*0.1-0.1,A3)
81690008169000.0=IF(COUNTIF($A$1:A4,A4)>1,A4+COUNTIF($A$1:A4,A4)*0.1-0.1,A4)
80690008069000.2=IF(COUNTIF($A$1:A5,A5)>1,A5+COUNTIF($A$1:A5,A5)*0.1-0.1,A5)
90340009034000.0=IF(COUNTIF($A$1:A6,A6)>1,A6+COUNTIF($A$1:A6,A6)*0.1-0.1,A6)
1000094810000948.0=IF(COUNTIF($A$1:A7,A7)>1,A7+COUNTIF($A$1:A7,A7)*0.1-0.1,A7)
1000094810000948.1=IF(COUNTIF($A$1:A8,A8)>1,A8+COUNTIF($A$1:A8,A8)*0.1-0.1,A8)
1000094810000948.2=IF(COUNTIF($A$1:A9,A9)>1,A9+COUNTIF($A$1:A9,A9)*0.1-0.1,A9)

<tbody>
</tbody>
 
Upvote 0

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