Formula to return count of unique values in one column, for each different value in another column

aldousjg

New Member
Joined
Jan 20, 2021
Messages
16
Office Version
  1. 365
Platform
  1. Windows
Hi all,

I'm having trouble with a formula which needs to return a count of unique names found in one column for each unique combination of number and date found in two other columns. Hopefully this example explains it a bit better:

1611650406804.png


So for the combination of 123 and 01/01/2000, there is one unique name in the Names column and a value of 1 is returned, but for the combination of 456 and 03/03/2000, there are three unique names in the names column and a value of 3 is returned.

My actual dataset is a few thousand rows and I would now be able to specify actual values of number or date in a formula.

Could anyone help?

Thank you,
 

Excel Facts

Which came first: VisiCalc or Lotus 1-2-3?
Dan Bricklin and Bob Frankston debuted VisiCalc in 1979 as a Visible Calculator. Lotus 1-2-3 debuted in the early 1980's, from Mitch Kapor.
You Can Use Countifs that have multiple criteria range and Criteria for each Range.
 
Upvote 0
count unique items with 2 conditions.xlsx
D
22
Blad1
Cell Formulas
RangeFormula
D2D2=SUM(IF(--FREQUENCY(IF(($A$2:$A$16&"|"&$B$2:$B$16=A2:A2&"|"&B2:B2),MATCH($C$2:$C$16,$C$2:$C$16,0)),IF(($A$2:$A$16&"|"&$B$2:$B$16=A2:A2&"|"&B2:B2),MATCH($C$2:$C$16,$C$2:$C$16,0)))>0,1))
Press CTRL+SHIFT+ENTER to enter array formulas.
 
Upvote 0
Solution
Another option
Excel Formula:
=ROWS(UNIQUE(FILTER($C$2:$C$1000,($A$2:$A$1000=A2)*($B$2:$B$1000=B2))))
 
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