How to Remove Duplicates of a Given Row using Formula?

gordonhtfu

New Member
Joined
Jan 9, 2014
Messages
9
Here is a sample (simplified) scenario that I am trying to resolve.

Given...
 TomPeterSamSusan
Combo11213
Combo2AABA
Combo3!@#$
Combo4abbc

<COLGROUP><COL style="WIDTH: 54pt" span=5 width=72><TBODY>
</TBODY>

Trying to make it into this by removing all the duplicates:
Combo1123 
Combo2AB  
Combo3!@#$
Combo4abc 

<COLGROUP><COL style="WIDTH: 54pt" span=5 width=72><TBODY>
</TBODY>

Is there any method using formula? I am preferring formula (over macro or advanced filter) because it would dynamically update the result if the value in given table changes.
 

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Hi,

You won't be able to have the original table values replaced as desired without VBA, though if you are happy with having a different table which updates to give your desired results then, assuming the original table as you give it is in the range A1:E5 (with headers in row 1 and column A), create another table (with identical dimensions and headers), enter this formula in the topleftmost cell and then copy across and down to fill the table:

=IF(COLUMNS($A:A)>SUMPRODUCT(1/COUNTIF($B2:$E2,$B2:$E2)),"",OFFSET(B2,,SUMPRODUCT(--(FREQUENCY(MATCH($B2:B2,$B2:B2,0),MATCH($B2:B2,$B2:B2,0))>1)),,))

Regards
 
Upvote 0
Hi,

You won't be able to have the original table values replaced as desired without VBA, though if you are happy with having a different table which updates to give your desired results then, assuming the original table as you give it is in the range A1:E5 (with headers in row 1 and column A), create another table (with identical dimensions and headers), enter this formula in the topleftmost cell and then copy across and down to fill the table:

=IF(COLUMNS($A:A)>SUMPRODUCT(1/COUNTIF($B2:$E2,$B2:$E2)),"",OFFSET(B2,,SUMPRODUCT(--(FREQUENCY(MATCH($B2:B2,$B2:B2,0),MATCH($B2:B2,$B2:B2,0))>1)),,))

Regards

Thank you. You are too smart.

How do you find the answer so quickly to random questions? :)
 
Upvote 0
Probably as I am fortunate enough to be able to see order within that apparent randomness! :)

Glad I could help and thanks for the feedback.

Regards
 
Upvote 0

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