I re-ran with the following (had tossed in the LTrim) and with spaces in front of and behind the fraction, it worked for me. Academic at this point per the excellent formula. Just in case you find any more weirdness in the pasted cells, you could try this. select the cell in question, and run:
Sub temp() Dim i AsInteger Dim strMsg AsString For i = 1 To Len(ActiveCell.Value)
strMsg = strMsg & vbCrLf & Asc(ActiveCell.Characters(i, 1).Text)
Next
MsgBox strMsg
EndSub
This should return the character code for ea character in the cell.
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