S.H.A.D.O.
Well-known Member
- Joined
- Sep 6, 2005
- Messages
- 1,915
Good evening,
I would like to cycle through all C(49,6) combinations and keep a count of the distribution for each combination for each of the different Sets.
By this I mean the following, there are 8 sets of numbers:-
Set 1 = 01,09,17,25,33
Set 2 = 02,10,18,26,34
Set 3 = 03,11,19,27,35
Set 4 = 04,12.20.28,36
Set 5 = 05,13,21,29,37
Set 6 = 06,14,22,30,38
Set 7 = 07,15,23,31,39
Set 8 = 08,16,24,32
So for the first combination 01,02,03,04,05,06 the distribution would be 111111 because the 6 numbers are from 6 different sets.
So for combination 09,17,28,31,32,38 the distribution would be 211110 because there are 2 numbers from one 1 Set and the other 4 numbers from 4 different sets.
So for combination 04,12,20,21,29,38 the distribution would be 321000 because there are 3 numbers from one Set, 2 numbers from another Set and 1 number from another different Set.
At the end I would like the GRAND total for ALL the posiible Sets please.
The Sets are:-
111111 = x combinations
211110 = x combinations
221100 = x combinations
222000 = x combinations
311100 = x combinations
321000 = x combinations
330000 = x combinations
411000 = x combinations
420000 = x combinations
510000 = x combinations
600000 = x combinations
Grand Total = x combinations
Here is the main code I have got so far:-
I have tried using Case statements etc but can't get even close.
Thanks in advance.
I would like to cycle through all C(49,6) combinations and keep a count of the distribution for each combination for each of the different Sets.
By this I mean the following, there are 8 sets of numbers:-
Set 1 = 01,09,17,25,33
Set 2 = 02,10,18,26,34
Set 3 = 03,11,19,27,35
Set 4 = 04,12.20.28,36
Set 5 = 05,13,21,29,37
Set 6 = 06,14,22,30,38
Set 7 = 07,15,23,31,39
Set 8 = 08,16,24,32
So for the first combination 01,02,03,04,05,06 the distribution would be 111111 because the 6 numbers are from 6 different sets.
So for combination 09,17,28,31,32,38 the distribution would be 211110 because there are 2 numbers from one 1 Set and the other 4 numbers from 4 different sets.
So for combination 04,12,20,21,29,38 the distribution would be 321000 because there are 3 numbers from one Set, 2 numbers from another Set and 1 number from another different Set.
At the end I would like the GRAND total for ALL the posiible Sets please.
The Sets are:-
111111 = x combinations
211110 = x combinations
221100 = x combinations
222000 = x combinations
311100 = x combinations
321000 = x combinations
330000 = x combinations
411000 = x combinations
420000 = x combinations
510000 = x combinations
600000 = x combinations
Grand Total = x combinations
Here is the main code I have got so far:-
Code:
Option Explicit
Option Base 1
Private Map(1 To 11) As Long
Const MinA As Integer = 1
Const MaxF As Integer = 49
Sub Distribution()
Dim A As Integer, B As Integer, C As Integer, D As Integer, E As Integer, F As Integer
Dim n As Long
Dim nDist(11) As Double
With Application
.ScreenUpdating = False: .Calculation = xlCalculationManual: .DisplayAlerts = False
End With
Map(1) = 111111
Map(2) = 211110
Map(3) = 221100
Map(4) = 222000
Map(5) = 311100
Map(6) = 321000
Map(7) = 330000
Map(8) = 411000
Map(9) = 420000
Map(10) = 510000
Map(11) = 600000
Columns("A:B").ClearContents
Cells(1, 1).Select
For A = MinA To MaxF - 5
For B = A + 1 To MaxF - 4
For C = B + 1 To MaxF - 3
For D = C + 1 To MaxF - 2
For E = D + 1 To MaxF - 1
For F = E + 1 To MaxF
' Calculation to go here.
Next F
Next E
Next D
Next C
Next B
Next A
For n = 1 To UBound(nDist)
ActiveCell.Offset(0, 0).Value = Map(n)
ActiveCell.Offset(0, 1).Value = nDist(n)
ActiveCell.Offset(1, 0).Select
Next n
ActiveCell.Offset(0, 1).FormulaR1C1 = "=Sum(R1C2:R[-1]C)"
With Application
.DisplayAlerts = True: .Calculation = xlCalculationAutomatic: .ScreenUpdating = True
End With
End Sub
I have tried using Case statements etc but can't get even close.
Thanks in advance.