Login used as a signature on a form

LMBradbury

New Member
Joined
Mar 8, 2023
Messages
9
Office Version
  1. 365
Platform
  1. Windows
Hello,

I have a PO Signature approval form (SignatureApprovalForm), that has a text box that when clicked opens the frm_login. This is where the allowed users can put their username and password, that when they click cmd_login logs them in. I would like to then have the username of be inputted into the a field on the SignatureApprovalForm, field named txt_approval. When I test, I am getting a debug of the below. Also here is my code.
VBA Code:
Private Sub cmd_login_Click()

  Dim db As DAO.Database
  Dim rst As DAO.Recordset
  Dim strSQL As String
  Dim strUser As String
  
 strUser = Me.txt_username

  If Trim(Me.txt_username.Value & vbNullString) = vbNullString Then
    MsgBox prompt:="Username should not be left blank.", buttons:=vbInformation, title:="Username Required"
    Me.txt_username.SetFocus
    Exit Sub
  End If
 
  If Trim(Me.txt_password.Value & vbNullString) = vbNullString Then
    MsgBox prompt:="Password should not be left blank.", buttons:=vbInformation, title:="Password Required"
    Me.txt_password.SetFocus
    Exit Sub
  End If
 
  'query to check if login details are correct
  strSQL = "SELECT FirstName FROM tbl_login WHERE Username = """ & Me.txt_username.Value & """ AND Password = """ & Me.txt_password.Value & """"
 
  Set db = CurrentDb
  Set rst = db.OpenRecordset(strSQL)
  If rst.EOF Then
    MsgBox prompt:="Incorrect username/password. Try again.", buttons:=vbCritical, title:="Login Error"
    Me.txt_username.SetFocus
  Else
    MsgBox prompt:="Hello, " & rst.Fields(0).Value & ".", buttons:=vbOKOnly, title:="Login Successful"
Forms!SignatureApprovalForm.txt_approval = strUser
DoCmd.Close acForm, "frm_login", acSaveYes
  End If
 
 Set db = Nothing
 Set rst = Nothing

End Sub

1679421011645.png


I am at a loss, and appreciate any insight.
 

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It suggests your control name is spelled incorrectly. Not likely that case matters, but if it's spelled correctly then I'd make sure the case matches in your code.
 
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