S.H.A.D.O.
Well-known Member
- Joined
- Sep 6, 2005
- Messages
- 1,915
Hi Everyone,
Six Numbers are drawn.
The code below cycles through a range of Six Number Combinations and produces a value of those covered for Five if Five is matched.
It basically tests for how many Five Number Combinations are covered in the Fifteen Six Number Combinations ( Cells G13:L27 ) with Numbers One to Twenty Four.
There are 42,504 Five Number Combinations of Twenty Four Numbers ( =COMBIN(24,5) ).
The code below produces a value of those that are covered out of the 42,504 Combinations ( Ninety, which is correct ).
How can the code below be adapted to ALSO calculate ( value to go in Cell O17 ) how many Combinations are covered for Three if Five Please.
I was Told for the Interpretation of the 3 if 5 Category that you Need to Cycle through ALL 5 Number Combinations that can be Constructed from the Total Numbers Used in the Wheel ( 24 in this Case ). So if the Wheel Contains "x" Unique Numbers, you Need to Cycle through ALL 5 Number Combinations from those "x" Numbers. Then you Need to Scan the Wheel for Each 5 Number Combination Produced and Compare it with Each Line in the Wheel to see if that Line Matches the 5 Number Combination in *EXACTLY* 3 Numbers. If it does, then that Combination of 3 if 5 is Covered and Added to the Total and there is NO Need to Continue to Check for that Particular Combination Any Further. You then go onto the Next Combination to Check and so on Until ALL Combinations have been Cycled through and Checked with the Wheel.
I hope I have explained this clearly enough.
Thanks in Advance.
All the Best.
SHADO
Six Numbers are drawn.
The code below cycles through a range of Six Number Combinations and produces a value of those covered for Five if Five is matched.
It basically tests for how many Five Number Combinations are covered in the Fifteen Six Number Combinations ( Cells G13:L27 ) with Numbers One to Twenty Four.
There are 42,504 Five Number Combinations of Twenty Four Numbers ( =COMBIN(24,5) ).
The code below produces a value of those that are covered out of the 42,504 Combinations ( Ninety, which is correct ).
How can the code below be adapted to ALSO calculate ( value to go in Cell O17 ) how many Combinations are covered for Three if Five Please.
I was Told for the Interpretation of the 3 if 5 Category that you Need to Cycle through ALL 5 Number Combinations that can be Constructed from the Total Numbers Used in the Wheel ( 24 in this Case ). So if the Wheel Contains "x" Unique Numbers, you Need to Cycle through ALL 5 Number Combinations from those "x" Numbers. Then you Need to Scan the Wheel for Each 5 Number Combination Produced and Compare it with Each Line in the Wheel to see if that Line Matches the 5 Number Combination in *EXACTLY* 3 Numbers. If it does, then that Combination of 3 if 5 is Covered and Added to the Total and there is NO Need to Continue to Check for that Particular Combination Any Further. You then go onto the Next Combination to Check and so on Until ALL Combinations have been Cycled through and Checked with the Wheel.
I hope I have explained this clearly enough.
Code:
Sub test_for_5()
Dim a, dic As Object
Set dic = CreateObject("scripting.dictionary")
a = Range("G13").CurrentRegion.Value
For i = 1 To UBound(a, 1)
For ii = 1 To 2
For iii = ii + 1 To 3
For iv = iii + 1 To 4
For v = iv + 1 To 5
For vi = v + 1 To 6
z = a(i, ii) & "," & a(i, iii) & a(i, iv) & a(i, v) & a(i, vi)
If Not dic.exists(z) Then
dic.Add z, Nothing
n = n + 1
End If
Next vi, v, iv, iii, ii, i
Set dic = Nothing
Range("O16") = n
End Sub
All the Best.
SHADO