Need Help with AND query

KAZSTREBOR

New Member
Joined
Feb 18, 2021
Messages
9
Office Version
  1. 365
Platform
  1. Windows
Hi there. I'm not sure if it is even possible to do what I want in access. I need to create a query that will count the number of records if two conditions are met. I have 2 columns "Date Order Placed" and "Date Order Received". I need to be able to report the amount of orders placed in each month and the amount of those orders received in each month. IE- Count of orders placed in Jan AND received in Jan, orders placed in Jan AND received in Feb, and so on. Everything I try gives me the count for one column or the other but not both. Any help is much appreciated.
 

Excel Facts

Difference between two dates
Secret function! Use =DATEDIF(A2,B2,"Y")&" years"&=DATEDIF(A2,B2,"YM")&" months"&=DATEDIF(A2,B2,"MD")&" days"
If there were 30 orders place in January and 20 received in January and you want the stats for January only, you expect to see
Placed = 30, Received = 20?
Probably a UNION query would be simple enough and provide that.

EDIT - Actually, a Totals query is probably more suitable.
 
Last edited:
Upvote 0
Something along the lines of
SQL:
SELECT Count(Tbl1.OrderDate) AS CountOfOrderDate, Count(Tbl1.ReceivedDate) AS CountOfRecDate
FROM Tbl1;
using your table and field names of course.
 
Upvote 0
I ran a mockup with some sample data. It involves 1 table and 2 queries. Results are below.

Table SampOrders
SampOrders SampOrders

IDOrderDateReceivedDate
1​
21-Jan-21​
27-Jan-21​
2​
10-Jan-21​
23-Jan-21​
3​
15-Jan-21​
07-Feb-21​
4​
17-Jan-21​
04-Mar-21​
5​
03-Feb-21​
16-Feb-21​
6​
14-Feb-21​
31-Mar-21​
7​
15-Jan-21​
05-Apr-21​
8​
12-Feb-21​
18-May-21​
9​
06-Apr-21​
23-Apr-21​
10​
08-Feb-21​
12-Feb-21​
11​
09-Feb-21​
08-Apr-21​
12​
12-Jan-21​
23-Jan-21​
13​
07-Apr-21​
17-Apr-21​
14​
11-Feb-21​
06-May-21​
Query1 OrderedReceivedQ

SELECT MonthName(Month(orderdate)) AS Ordered
, MonthName(Month(receiveddate)) AS Received
, 1 AS Num, Month([OrderDate]) AS O
, Month([receiveddate]) AS R
FROM samporders
ORDER BY Month([OrderDate])
, Month([receiveddate]);

Query2 OrderedReceivedFinalCountsQ

SELECT OrderedReceivedQ.Ordered
, OrderedReceivedQ.Received
, Count(OrderedReceivedQ.Num) AS CountOfNum
FROM OrderedReceivedQ
GROUP BY OrderedReceivedQ.Ordered
, OrderedReceivedQ.Received
, OrderedReceivedQ.O
, OrderedReceivedQ.R
ORDER BY OrderedReceivedQ.O
, OrderedReceivedQ.R;

Tested Output:

OrderedReceivedFinalCountsQ OrderedReceivedFinalCountsQ

OrderedReceivedCountOfNum
JanuaryJanuary
3​
JanuaryFebruary
1​
JanuaryMarch
1​
JanuaryApril
1​
FebruaryFebruary
2​
FebruaryMarch
1​
FebruaryApril
1​
FebruaryMay
2​
AprilApril
2​
 
Upvote 0
Solution
I ran a mockup with some sample data. It involves 1 table and 2 queries. Results are below.

Table SampOrders
SampOrders SampOrders

IDOrderDateReceivedDate
1​
21-Jan-21​
27-Jan-21​
2​
10-Jan-21​
23-Jan-21​
3​
15-Jan-21​
07-Feb-21​
4​
17-Jan-21​
04-Mar-21​
5​
03-Feb-21​
16-Feb-21​
6​
14-Feb-21​
31-Mar-21​
7​
15-Jan-21​
05-Apr-21​
8​
12-Feb-21​
18-May-21​
9​
06-Apr-21​
23-Apr-21​
10​
08-Feb-21​
12-Feb-21​
11​
09-Feb-21​
08-Apr-21​
12​
12-Jan-21​
23-Jan-21​
13​
07-Apr-21​
17-Apr-21​
14​
11-Feb-21​
06-May-21​
Query1 OrderedReceivedQ

SELECT MonthName(Month(orderdate)) AS Ordered
, MonthName(Month(receiveddate)) AS Received
, 1 AS Num, Month([OrderDate]) AS O
, Month([receiveddate]) AS R
FROM samporders
ORDER BY Month([OrderDate])
, Month([receiveddate]);

Query2 OrderedReceivedFinalCountsQ

SELECT OrderedReceivedQ.Ordered
, OrderedReceivedQ.Received
, Count(OrderedReceivedQ.Num) AS CountOfNum
FROM OrderedReceivedQ
GROUP BY OrderedReceivedQ.Ordered
, OrderedReceivedQ.Received
, OrderedReceivedQ.O
, OrderedReceivedQ.R
ORDER BY OrderedReceivedQ.O
, OrderedReceivedQ.R;

Tested Output:

OrderedReceivedFinalCountsQ OrderedReceivedFinalCountsQ

OrderedReceivedCountOfNum
JanuaryJanuary
3​
JanuaryFebruary
1​
JanuaryMarch
1​
JanuaryApril
1​
FebruaryFebruary
2​
FebruaryMarch
1​
FebruaryApril
1​
FebruaryMay
2​
AprilApril
2​
This worked great, thank you!
 
Upvote 0
You are very welcome. Good luck with your project.
 
Upvote 0

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