ram_Sathish
New Member
- Joined
- Jun 12, 2006
- Messages
- 15
Hi All,
I tried opening an access application through creating an object of the access application in VB 6.0 by giving the following codes.
set obj =createobject ("access.application")
set obj1=obj.openaccessproject("Path of the file")
i am unable to open an access application.
please help me out.
thanks
I tried opening an access application through creating an object of the access application in VB 6.0 by giving the following codes.
set obj =createobject ("access.application")
set obj1=obj.openaccessproject("Path of the file")
i am unable to open an access application.
please help me out.
thanks