RANDBETWEEN WITH IF CONDITIONS

NAGARAJAN_EXCEL

New Member
Joined
Sep 29, 2020
Messages
5
Office Version
  1. 2019
Platform
  1. Windows
1601379518147.png

A=RANDBETWEEN (117,151)
B=RANDBETWEEN (10.8,13.4)
C=RANDBETWEEN(D-20,D+20)
D=RANDBETWEEN(68,92)
E=C/D
F=((0.48*B*((A)/E)/1000))
G=(6700-(5*25))*F*((1/(500-25))-(1/(800-25)))*0.9

THIS FORUMULA, I have given in cells
BUT I REQUIRE
F <1.250
G>2.220
H= IF(AND(F <1.250,G>2.220),"OK","WRONG")

IS IT POSSIBLE, PLEASE GUIDE ME HOW TO DO
 
MrExcel_RANDBETWEEN WITH IF CONDITIONS.xlsx
ABCDEFGH
1ABCDEFGComment
214011,676880,8636363640,9026021054,3527182
3F has to be at least:0,4603506552,22
4Minimum F will be achieved by applying:
511710,888681,2941176470,468680727Ok
6
7Maximum F is achieved by applying:
815113,448680,7058823531,375912Wrong
9
10F is safely below 1.25 by applying:
1115113,452,8350208680,77698561,2499999999999800Ok
12
13So the general formula could be:
1412011,898901,0888888890,6241959183,0101292Ok
Sheet1
Cell Formulas
RangeFormula
A2,A14A2=RANDBETWEEN(117,151)
B2,B14B2=RANDBETWEEN(108,134)/10
C2C2=RANDBETWEEN(D2-20,D2+20)
D2,D14D2=RANDBETWEEN(68,92)
E2,E14,E11,E8,E5E2=C2/D2
F2,F14,F11,F8,F5F2=0.48*B2*A2/E2/1000
G14,G2:G3G2=(6700-(5*25))*F2*((1/(500-25))-(1/(800-25)))*0.9
C5C5=D5+20
C8C8=D8-20
H8,H11H8=IF(F8<1.25,"Ok","Wrong")
C11C11=D11-MIN(20,D11-A11*B11*D11*0.48/1250-0.000000000001)
C14C14=RANDBETWEEN(D14-MIN(20,D14-A14*B14*D14*0.48/1250-0.000000000001),D14+20)
H14H14=IF(AND(F14<1.25,G14>2.22),"Ok","Wrong")
 
Last edited:
Upvote 0

Excel Facts

What did Pito Salas invent?
Pito Salas, working for Lotus, popularized what would become to be pivot tables. It was released as Lotus Improv in 1989.
As Joeu2004 mentioned, the ROUNDUP is necessary (here in C14):
VBA Code:
=RANDBETWEEN(D14-ROUNDDOWN(MIN(20,D14-A14*B14*D14*0.48/1250-0.000000000001),0),D14+20)
which is
VBA Code:
=RANDBETWEEN(MAX(D14-20,ROUNDUP(A14*B14*D14*0.48/1250+0.000000000001),0),D14+20)
 
Last edited:
Upvote 0

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