Random distribution of 4 values approximately 25%

motilulla

Well-known Member
Joined
Feb 13, 2008
Messages
2,360
Office Version
  1. 2010
Hello,

In the column "C" I have value1 and in the column "B" I have got Value2
In the column "E" I have join both value1 & value2 using formula E6 = C6&D6

Column F has 50 numbers I want to fill in the column "G" "4 join values are in the "E"
Randomly distributing approximately 25% each of these 4 values. As shown in the attach example image.

*ABCDEFGHI
1
2
3
425,00%
5Value1Value2JoinNumDistribution
60000100
70M0M20M
8111130M
91M1M40M
10511
1161M
12711
1381M
14900
151000
161111
171211
18130M
19140M
201500
21160M
22170M
23180M
241911
25201M
262111
27221M
282300
292400
302511
312611
32270M
33280M
342900
35300M
36310M
37320M
383311
39341M
403511
41361M
423700
433800
443911
454011
46410M
47420M
48431M
494411
50451M
514600
524700
534811
544911
55500M
56
57

Thank you all.

I am using Excel 2000

Regards,
Moti
 

Attachments

  • Distribution 25%.png
    Distribution 25%.png
    33.5 KB · Views: 4

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Solution
Maybe:

Book1
ABCDEFG
1
2
3
425,00%
5Value1Value2JoinNumDistribution
610000010M
7150M0M20M
813111130M
9121M1M41M
1051M
11600
1270M
13800
1490M
15100M
161111
17120M
181311
191400
20151M
21160M
221700
231800
241911
252000
26211M
272200
28231M
29241M
30251M
312611
32271M
33280M
342900
353011
363100
37321M
383311
39340M
403500
41360M
423711
433811
44390M
45401M
464111
47421M
484311
49441M
504511
514611
52470M
53480M
54490M
555011
Sheet3
Cell Formulas
RangeFormula
A6:A9A6=COUNTIF($G$6:$G$55,E6)
E6:E9E6=C6&D6
G6:G55G6=INDEX($E$6:$E$9,INT(RAND()*4)+1)
Eric W, yes it is simple and perfect solution I like it.

Thank you for your help and time you gave.

Good Luck!

Kind Regards,
Moti :)
 
Upvote 0

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