rounding in vba

[MetLife]

Hi,

I am a little confused by the following rounding

tt = Round(1915.5 * 3.27, 2)

1915.5 * 3.27 = 6263.685

so the rounding should round up 5 to 6263.69 but I am getting 6263.68

What is happening?

This is excel 2016

Thanks

 

[JoeMo]

The VBA Round function rounds down on a 5, while the worksheet Round function rounds up on a 5.

From the VBE Immediate Window:

?Round(6263.685,2)
6263.68
?worksheetfunction.Round(6263.685,2)
6263.69

 

[MetLife]

So i have to go through my entire code and change

Round to
Application.round?

It seems strange the functions work in different ways

 

[joeu2004]

It might seem strange, but that's the way it is. VBA Round is called "banker's rounding".

But JoeMo described VBA Round incorrectly. It does not always round 5 down. Instead, it rounds to even. So Round(123.5) is 124. And Round (122.5) is 122.

 

[Rick Rothstein]

It might seem strange, but that's the way it is. VBA Round is called "banker's rounding".

But JoeMo described VBA Round incorrectly. It does not always round 5 down. Instead, it rounds to even. So Round(123.5) is 124. And Round (122.5) is 122.

To follow up on joeu2004's comment, VBA uses Banker's Rounding for all rounding that it does, even implicit rounding (such as assigning a floating point number to an integer variable as but one example), except for one lone function... the Format function... it does the same kind of rounding as Excel's worksheet functions. So, if you change this code line...

tt = Round(1915.5 * 3.27, 2)

to this either this...

tt = Format(1915.5 * 3.27, "0.##")

or this...

tt = Format(1915.5 * 3.27, "0.00")

(depending on whether the output needs to contain 2 visible decimal places or not) you will get the rounded result you are looking for.