Shift cells left if adjacent columns are blank using VBA

Trebor8484

Board Regular
Joined
Oct 27, 2018
Messages
69
Office Version
  1. 2013
Platform
  1. Windows
Hi all,

Can anyone assist with a vba solution to the below problem please.

So I have from column I to column R columns labelled as follows:

Job Desc 1
Quantity 1
Job Desc 2
Quantity 2
Job Desc 3
Quantity 3
Job Desc 4
Quantity 4
Job Desc 5
Quantity 5

What I need to do is, working from right to left identify if there are any charges listed in Job Desc 5/Quantity 5. If there are but Job Desc 4/Quantity 4 are empty then it needs to move the values from Job Desc 5/Quantity 5 into Job Desc 4/Quantity 4. Basically, there can be no empty columns. If there are charges then they need to be populated in Job Desc 1/Quantity 1 first before moving across.


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Thanks
 

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See if this does what you want...
Code:
[table="width: 500"]
[tr]
	[td]Sub ShiftLeftColumnItoR()
  Dim LastRow As Long
  LastRow = Columns("I:R").Find("*", , xlValues, , xlRows, xlPrevious, , , False).Row
  Range("I2:R" & LastRow).SpecialCells(xlBlanks).Delete xlShiftToLeft
End Sub[/td]
[/tr]
[/table]
 
Upvote 0
Thanks Rick, that works great

I was thinking I would end up having to write a for loop with range offsets and lots of copy and pasting. Didn't realise a one liner would do it....!
 
Upvote 0
Rick, I have found an issue with this where if there are values in adjacent columns, for example column S then it shifts them as well. I need it to ignore anything that isn't in the specified range I:R
 
Upvote 0

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