"Subscript out of range" error when using variables as worksheet reference

msthiagu

New Member
Joined
May 20, 2022
Messages
7
Office Version
  1. 365
Platform
  1. Windows
Hi. I have been using excel macro as below and experiencing "Runtime error 9: Subscript out of range" error. It happens only when I use a variable to reference a worksheet within a workbook.
vbaerror.PNG
 
Hi,
try changing this line

VBA Code:
Set wsdest1 = wb1.Sheets(shname1)

for this

VBA Code:
Set wsdest1 = wb1.Worksheets(CStr(shname1))

and see if resolves your issue

Dave
Tried the same. The error still persists. Attached screenshot of code.
vbaerror3.PNG
 
Upvote 0

Excel Facts

What does custom number format of ;;; mean?
Three semi-colons will hide the value in the cell. Although most people use white font instead.
If still getting the error then can only agree with @RoryA that sheet name does not exist. Worth checking the range names for spaces & typo's.
Perhaps if still an issue, helpful if place a copy of your workbook with dummy data on a file sharing site like dropbox & provide a link to it.

BTW - when posting code, use code tags from Menu Bar > VBA then place your code between the tags.

Dave
 
Upvote 0
If you change the set wsdest1 line to the below, does it still error out ?

VBA Code:
        Set wsdest1 = wb1.Sheets(Trim(shname1))
 
Upvote 0
If you want to try this:

VBA Code:
Sub Service_Transfer_Action_Items()

    Dim wb1 As Workbook
    Dim wscopy1 As Worksheet, wsdest1 As Worksheet, wsininterim1 As Worksheet
    Dim shname1 As String
    Dim a As Long, b As Long, lrow2 As Long, lrow3 As Long
    Dim sFailed As String
   
    Set wb1 = ActiveWorkbook
    Set wscopy1 = wb1.Worksheets("SCM")
    lrow2 = wscopy1.Cells(Rows.Count, "A").End(xlUp).Row
   
    sFailed = "Sheet(s) not found: "
    For a = 3 To lrow2
        shname1 = wscopy1.Cells(a, 1).Value
        On Error Resume Next
            Set wsdest1 = wb1.Sheets(Trim(shname1))
            If Err Then
                sFailed = sFailed & " " & shname1
            End If
        On Error GoTo 0
        With Application
            b = .IfError(.Match(wscopy1.Range("F" & a), wsdest1.Range("D:D"), 0), 0)
        End With
            If b <> 0 Then
                wscopy1.Range("G" & a & ":L" & a).Copy _
                    wsdest1.Range("E" & b & ":J" & b)
            End If
    Next a
   
    If sFailed <> "Sheet(s) not found: " Then
        MsgBox sFailed
    Else
        MsgBox "Completed"
    End If

End Sub
 
Upvote 0
If you want to try this:

VBA Code:
Sub Service_Transfer_Action_Items()

    Dim wb1 As Workbook
    Dim wscopy1 As Worksheet, wsdest1 As Worksheet, wsininterim1 As Worksheet
    Dim shname1 As String
    Dim a As Long, b As Long, lrow2 As Long, lrow3 As Long
    Dim sFailed As String
  
    Set wb1 = ActiveWorkbook
    Set wscopy1 = wb1.Worksheets("SCM")
    lrow2 = wscopy1.Cells(Rows.Count, "A").End(xlUp).Row
  
    sFailed = "Sheet(s) not found: "
    For a = 3 To lrow2
        shname1 = wscopy1.Cells(a, 1).Value
        On Error Resume Next
            Set wsdest1 = wb1.Sheets(Trim(shname1))
            If Err Then
                sFailed = sFailed & " " & shname1
            End If
        On Error GoTo 0
        With Application
            b = .IfError(.Match(wscopy1.Range("F" & a), wsdest1.Range("D:D"), 0), 0)
        End With
            If b <> 0 Then
                wscopy1.Range("G" & a & ":L" & a).Copy _
                    wsdest1.Range("E" & b & ":J" & b)
            End If
    Next a
  
    If sFailed <> "Sheet(s) not found: " Then
        MsgBox sFailed
    Else
        MsgBox "Completed"
    End If

End Sub
Thanks Alex. This has helped me drill down the root cause. Error found to be with a wrong sheet number referenced.

The code works fine now. I have taken cues from your code and made few changes in my code to make it work. Thanks again.

Regards
Thiagarajan M.S.
 
Upvote 0
I have taken cues from your code and made few changes in my code to make it work.
Good to hear you fixed your code and it works without problems now. However, that would be great if you could post the working code to help future readers, then it is perfectly fine to mark it as the solution.
You can also mark another post that helped you most solving your question if you can't share your code. Otherwise, please do not mark a post that doesn't contain a solution.
 
Upvote 0

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