QIBusinessGroup
New Member
- Joined
- Jan 23, 2011
- Messages
- 5
Hello all,
I am having trouble converting my Excel 2007 formula to Excel 2003.
What I am trying to do is have excel count the number of occurance in one cell based upon dates in another cell.
Here is the formula in 2007 (which works perfectly)
=SUMPRODUCT(--(CaseTracker!$K:$K="Follow-Up"),--(CaseTracker!$N:$N>=$N8),--(CaseTracker!$N:$N<=$O8))
However when I emailed it to a co-worker who has 2003 i got #num errors.
I attempted to modify it in excel 2003 with this formula
=COUNTIF(CaseTracker!$K:$K,"Follow-Up")-COUNTIF(CaseTracker!$E:$E,">="&$N7)-COUNTIF(CaseTracker!$E:$E,">="&$O7)
and
=SUMPRODUCT(--(CaseTracker!N8:N1500<=1/1/2011),--(CaseTracker!N8:N1500>=1/7/2011),--(CaseTracker!K8:K1500="Follow-Up"))
however both formulas give me the wrong number. Can anyone tell me what I am doing wrong.
P.s. Column N and O contains dates. N is start date and O is end date.
if you need me to provide additional info please email me at QIBusinessGroup@Gmail.com
Thank you in advance for any assistance it will be greatly appriciated and received.
I am having trouble converting my Excel 2007 formula to Excel 2003.
What I am trying to do is have excel count the number of occurance in one cell based upon dates in another cell.
Here is the formula in 2007 (which works perfectly)
=SUMPRODUCT(--(CaseTracker!$K:$K="Follow-Up"),--(CaseTracker!$N:$N>=$N8),--(CaseTracker!$N:$N<=$O8))
However when I emailed it to a co-worker who has 2003 i got #num errors.
I attempted to modify it in excel 2003 with this formula
=COUNTIF(CaseTracker!$K:$K,"Follow-Up")-COUNTIF(CaseTracker!$E:$E,">="&$N7)-COUNTIF(CaseTracker!$E:$E,">="&$O7)
and
=SUMPRODUCT(--(CaseTracker!N8:N1500<=1/1/2011),--(CaseTracker!N8:N1500>=1/7/2011),--(CaseTracker!K8:K1500="Follow-Up"))
however both formulas give me the wrong number. Can anyone tell me what I am doing wrong.
P.s. Column N and O contains dates. N is start date and O is end date.
if you need me to provide additional info please email me at QIBusinessGroup@Gmail.com
Thank you in advance for any assistance it will be greatly appriciated and received.