Troubleshooting Complex Nested If and If Functions

Stelchar

New Member
Joined
Oct 31, 2013
Messages
1
I'm having an issue with my nested if function. What I would ideally like to do is to compare 2 cells against a confidence interval percentage. So, if cell A is 5% higher than cell B I want my function to create a label the next cell as "Higher" and if its 10% higher than to be labeled as "Much Higher" and the same for 5% lower "Lower" and 10% lower "Much Lower" and if the values of both cells are the same the label to be "Same"
I have created a nested if function already....
=IF(D5<(C6*('Rating Legend'!$B$2*2)),"Much Lower",IF(D5<(C6-(C6*'Rating Legend'!$B$2)),"Lower",IF(D5>C6+(C6*'Rating Legend'!$B$2),"Higher",IF(D5>C6+(C6*('Rating Legend'!$B$2*2)),"Much Higher","Same"))))
*rating legend is on a separate worksheet where the confidence interval is located*
but can't seem to get the "much higher" portion to work properly. I have tried reversing the order but it still does not work properly...any feedback is welcome. Please!
 

AhoyNC

Well-known Member
Joined
Oct 10, 2011
Messages
4,344
Office Version
365
Platform
Windows
You need to give Higher a range of values. Right now your formula will always return a True if D5>C6+(C6*Rating).
See the example below where I used the AND function to set a top and bottom range.
In this example If A1 is greater than B1+1 and less than or equal to B1+4 then HIGH. If greater than B1+4 then MUCH HIGHER.

There are two formulas shown below and you might be able to shorten your formula like the one in C2.

Excel Workbook
ABCD
11510
2
3
Sheet3
 

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