Trying to get the opposite effect of LOG function

RRAAC

New Member
Joined
Jul 23, 2019
Messages
1
Hello,

I'm trying to weight a score so that the closer it is to the top the smaller the increments are. For example, if someone scored 2.1 then they would get 100, if they get 2.5 then say 99, then 3.5 might be 96 etc. the further away you get from 2.5 the more severe the drop in score.

When I ran the following table (see below) I used the formula

ROUND(LOG(A$2,A2)*100,0)
ROUND(LOG(A$2,A3)*100,0)
ROUND(LOG(A$2,A4)*100,0)
...
etc.

But the problem with LOG is that going from 2.1 to 2.5 is too severe a drop until around 12 where the decline is score becomes quite flat. I want it to start "flat" and get more severe the further down the list.

Advice would be much appreciated!

RateScore
2.1100
2.581
368
3.559
454
4.549
546
5.544
641
6.540
738
7.537
836
8.535
934
9.533
1032
10.532
1131
11.530
1230
12.529
1329
13.529
1428
14.528
1527
15.527
1627
16.526
1726
17.526
1826
18.525
1925
19.525
2025

<tbody>
</tbody>
 

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What did Pito Salas invent?
Pito Salas, working for Lotus, popularized what would become to be pivot tables. It was released as Lotus Improv in 1989.
G'day RRAAC,

I have experimented with your formula to get it to flatten at the top and then drop away and the best I could get is this
=ROUND(LOG(A$2,22.1-A2)*100,1)
however, that is probably way too flat at the top, 4.0 still being 99%.

I'm not enough of a mathematician to know how to go any further, but you could design your own curve and use vlookup to fill in the data.

Cheers

shane
 
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