Using Loop in Goal Seek

SonicBoomGolf

Active Member
Joined
Aug 7, 2004
Messages
325
I am trying to use VBA to Loop a Goal Seek, but for some reason it is not working. Below is my code.

Do
If Not Selection.Value > "" Then Exit Do
Range("aa2").GoalSeek Goal:=44500, ChangingCell:=Range("z2")
Loop

End Sub

In the sample below, column T is the original figure and column Z is the Goal Seek Result. When I run the "Range("aa2").GoalSeek Goal:=44500, ChangingCell:=Range("z2")" portion of the above code it works, but I cannot get it to loop to the bottom of my data like I want. So basically I am having trouble with the code looping to the bottom of my data. Any ideas?
Sylvester - Trans Cost Analysis.xls
TUVWXYZAA
1NumberofChepPalletsAvg.CHEPWeightTotalPalletWeightTotalPalletWeightPlusProductWeightExcessWeightAveWeight/PalletNumberofChepPalletsTotalWeight
2256516257239327,8932,8311544,500
329651885497135,2131,6492949,713
429651885483973,8971,6042948,397
529651885482473,7471,5992948,247
627651755481353,6351,7182748,135
727651755480463,5461,7142748,046
827651755479493,4491,7112747,949
926651690479153,4151,7782647,915
1025651625478943,3941,8512547,894
1127651755478893,3891,7092747,889
1227651755478563,3561,7072747,856
Sylvester
 

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Hi, trackman69,

so you want to loop from aa2 and z2 to aa200 and z200 (considering that 200 is your last row)

how to find the last cell of your data:
Range("AA65536").End(xlUp).Select

how to loop through cells ?
For i = 2 To 5
MsgBox Cells(i, 27)
Next

result:

Code:
Dim lr as Long
Dim i as Long
lr = Range("AA65536").End(xlUp).Row
For i = 1 To lr
If Cells(i, 27) <> "" Then Cells(i, 27).GoalSeek Goal:=44500, ChangingCell:=Cells(i, 26)
Next i
It's not clear for me what you mean with If Not Selection.Value > "" , so I replaced it with something similar ...

does this give you a start
(I hope so: time to sleep for me)
kind regards,
Erik
 
Upvote 0
When I try this out, I am told that the reference is not valid and then it highlights in yellow the underlined portion of the code below. I don't understand why it is not working cause it looks fine.


Dim lr As Long
Dim i As Long
lr = Range("AA65536").End(xlUp).Row
For i = 1 To lr
If Cells(i, 27) <> "" Then Cells(i, 27).GoalSeek Goal:=44500, ChangingCell:=Cells(i, 26)
Next i

P.S. This is a good start for me. Thanks.
 
Upvote 0
trackman,

I'm not very good in theoretical approach of error messages...
Are you sure that Cells(i, 27) is always a formula? (but I don't know what it has to do with referencing)

a good thing to do is break up your code in little pieces and then pass through hitting F8 go to the different variables with your mouse: the actual value will be highlighted... Or place some Msgboxes

Dim lr As Long
Dim i As Long
lr = Range("AA65536").End(xlUp).Row
Msgbox lr
For i = 1 To lr
Cells(i, 27).Select 'no error ?
Cells(i, 26).Select
Msgbox Cells(i, 27) <> "" 'True or False
If Cells(i, 27) <> "" Then Cells(i, 27).GoalSeek Goal:=44500, ChangingCell:=Cells(i, 26)
Next i

I just tried out with a simple example. Protecting the worksheet you get Error 1004 Reference not valid (translated from dutch)
Is your sheet protected and are the cells to change locked?

kind regards,
Erik
 
Upvote 0
The first solution you gave worked. The problem was that i = 1 to lr. When I tried i = 2 to lr it worked. There was no data to analyze for Goal Seek in row 1. This was my first attempt at declaring a variable for looping. Thanks for the help!!!

This worked......

Dim lr As Long
Dim i As Long
lr = Range("AA65536").End(xlUp).Row
For i = 2 To lr
If Cells(i, 27) <> "" Then Cells(i, 27).GoalSeek Goal:=44500, ChangingCell:=Cells(i, 26)
Next i
 
Upvote 0
YEH! Computers behave as silly as we tell them to do!
:rolleyes:
If we tell them to search for a mountain in our house, they will say: can't find a mountain. :oops: Most of the time they don't say: mountains can't be found in houses! o_O It would still be easier to debug. :wink:
 
Upvote 0

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