using macro to open a csv file with a file name that changes

tuckercs

New Member
Joined
Mar 1, 2019
Messages
3
I am trying create a macro that will open a .csv file. The file name changes daily. The file name is YYYYMMDD_7dat.csv. Is there a formula that I can put in VBA that will format the open from to this format?
 

Excel Facts

Test for Multiple Conditions in IF?
Use AND(test, test, test, test) or OR(test, test, test, ...) as the logical_test argument of IF.
To specify the current date's file:
Code:
"C:\path\to\folder\" & Format(Date, "YYYYMMDD") & "_7dat.csv"
 
Upvote 0
Here is a copy of the macro I am trying to run. All the red text is the text I need to adjust with the current date.
Sub Transfer()
'
' Transfer Macro
'


'
ActiveWorkbook.Queries.Add Name:="20190304_7dat", Formula:= _
"let" & Chr(13) & "" & Chr(10) & " Source = Csv.Document(File.Contents(""C:\Users\C Tuck\Documents\DATREPORTS\20190304_7dat.csv""),[Delimiter="","", Columns=3, Encoding=65001, QuoteStyle=QuoteStyle.None])," & Chr(13) & "" & Chr(10) & " #""Promoted Headers"" = Table.PromoteHeaders(Source, [PromoteAllScalars=true])," & Chr(13) & "" & Chr(10) & " #""Changed Type"" = Table.TransformColumnTypes(#""Promoted Headers"",{{""SKU"", type text}, {""Qty" & _
" Sold"", Int64.Type}, {""ASIN"", type text}})" & Chr(13) & "" & Chr(10) & "in" & Chr(13) & "" & Chr(10) & " #""Changed Type"""
ActiveWorkbook.Worksheets.Add
With ActiveSheet.ListObjects.Add(SourceType:=0, Source:= _
"OLEDB;Provider=Microsoft.Mashup.OleDb.1;Data Source=$Workbook$;Location=20190304_7dat;Extended Properties=""""" _
, Destination:=Range("$A$1")).QueryTable
.CommandType = xlCmdSql
.CommandText = Array("SELECT * FROM [20190304_7dat]")
.RowNumbers = False
.FillAdjacentFormulas = False
.PreserveFormatting = True
.RefreshOnFileOpen = False
.BackgroundQuery = True
.RefreshStyle = xlInsertDeleteCells
.SavePassword = False
.SaveData = True
.AdjustColumnWidth = True
.RefreshPeriod = 0
.PreserveColumnInfo = True
.ListObject.DisplayName = "_20190304_7dat"
.Refresh BackgroundQuery:=False
End With
End Sub

What would I need to substitute for this in the macro.

Thanks in advance.
 
Upvote 0

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