variable using formula

Ingemar

New Member
Joined
May 8, 2017
Messages
23
Office Version
  1. 365
Platform
  1. Windows
Hello Excel users

The following two rows works fine. They check if value in cell C4 is correct (202102) and return the value in a modified shape to the cell A1 (2021-02).

Range("A1").Select
ActiveCell.FormulaR1C1 = "=IF(AND(ISNUMBER(R[3]C[2]),LEN(R[3]C[2])=6),LEFT(R[3]C[2],4)&""-""&RIGHT(R[3]C[2],2),"""")"


I have tried to create a variable, using the formula below, which is a minor modification from the formula above, but I only get the result "FALSE" in the Message box.

Yearandmonth = FormulaR1C1 = "=IF(AND(ISNUMBER(R[3]C[2]),LEN(R[3]C[2])=6),LEFT(R[3]C[2],4)&""-""&RIGHT(R[3]C[2],2),"""")"
MsgBox Yearandmonth

I am grateful for any help.

Kind regards

Ingemar
 

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Perhaps:

VBA Code:
Dim Yearandmonth As String

With Range("A1")
    .Formula = "=IF(AND(ISNUMBER(C4),LEN(C4)=6),LEFT(C4,4) & ""-"" & RIGHT(C4,2),"""")"
    Yearandmonth = .Value
End With

'or

With Range("C4")
    If (IsNumeric(.Value) And Len(.Value) = 6) Then Yearandmonth = Left(.Value, 4) & "-" & Right(.Value, 2)
End With
 
Upvote 0
Dear Stephen,

I have tested the first alternative and it works great. T H A N K Y O U very much for the help!


Kind regards

Ingemar
 
Upvote 0

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