VBA - Splitting a long line of code on to seperate lines

lemondifficult

New Member
Joined
Mar 19, 2014
Messages
40
Hi,

there is probably a very simple solution to this, however i cant seem to find it. Im looking to create a macro that hides around 300 specific lines of a spreadsheet.

I have the code written, however when compiling i get a syntax error probably because one of the lines is extremely long. Can anyone help me in putting this code in a format that will work? I have provided the code below;

Code:
    Sub Macro3()
Range("13:13,16:16,19:19,22:22,25:25,28:28,31:31,34:34,37:37,40:40,43:43,46:46,49:49,52:52,55:55,58:58,61:61,64:64,67:67,70:70,73:73,76:76,79:79,82:82,85:85,88:88,91:91,94:94,97:97,100:100,103:103,106:106,109:109,112:112,115:115,118:118,121:121,124:124,127:127,130:130,133:133,232:232,235:235,238:238,241:241,244:244,247:247,250:250,253:253,256:256,259:259,262:262,265:265,268:268,271:271,274:274,277:277,280:280,283:283,286:286,289:289,292:292,295:295,298:298,301:301,304:304,307:307,310:310,313:313,316:316,319:319,322:322,325:325,328:328,331:331,334:334,337:337,340:340,343:343,346:346,349:349,352:352,355:355,358:358,361:361,364:364,367:367,370:370,373:373,376:376,379:379,382:382,385:385,388:388,391:391,394:394,397:397,400:400,403:403,406:406,409:409,412:412,415:415,418:418,421:421,424:424,427:427,430:430,433:433,436:436,439:439,442:442,445:445,448:448,451:451,454:454,457:457,460:460,463:463,466:466,469:469,472:472,475:475,478:478,481:481,484:484,487:487,490:490,493:493,496:496,499:499,502:502,505:505,508:508,511:511,514:514,517:517,520:520,523:523,526:526,529:529,532:532,535:535,538:538,541:541,544:544,547:547,550:550,553:553,556:556,559:559,562:562,565:565,568:568,571:571,574:574,577:577,580:580,583:583,586:586,589:589,592:592,595:595,598:598,601:601,604:604,607:607,610:610,613:613,616:616,619:619,622:622,625:625,628:628,631:631,634:634,637:637,640:640,643:643,646:646,649:649,652:652,655:655,658:658,661:661,664:664,667:667,670:670,673:673,676:676,679:679,682:682,685:685,688:688,691:691,694:694,697:697,700:700,703:703,706:706,709:709,712:712,715:715,718:718,721:721,724:724,727:727,730:730,733:733,736:736,739:739,742:742,745:745,748:748,751:751,754:754,757:757,760:760,763:763,766:766,769:769,772:772,775:775,778:778,781:781,784:784,787:787,790:790,793:793,796:796,799:799,802:802,805:805,808:808,811:811,814:814,817:817,820:820,823:823,826:826,829:829,832:832,835:835,838:838,841:841,844:844,847:847,850:850,853:853,856:856,859:859,862:862,865:865,868:868,871:871,874:874,877:877,880:880,883:883,886:886,889:889,892:892,895:895,898:898,901:901,904:904,907:907,910:910,913:913,136:136,139:139,142:142,145:145,148:148,151:151,154:154,157:157,160:160,163:163,166:166,169:169,172:172,175:175,178:178,181:181,184:184,187:187,190:190,193:193,196:196,199:199,202:202,205:205,208:208,211:211,214:214,217:217,220:220,223:223,226:226,229:229").Select
    Range("F913").Activate
    Selection.EntireRow.Hidden = True
End Sub

any help is appreciated. thanks in advance.

Micheal
 

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Remove leading & trailing spaces
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Fluff

MrExcel MVP, Moderator
Joined
Jun 12, 2014
Messages
46,311
Office Version
  1. 365
Platform
  1. Windows
Hiya
I haven't checked all your numbers, but it looks to be in steps of 3, so how about something like this
Code:
Sub ThreeRws()

    Dim i As Integer

    For i = 13 To 913 Step 3
        Rows(i).Hidden = True
    Next i

End Sub
HTH
 

RoryA

MrExcel MVP, Moderator
Joined
May 2, 2008
Messages
35,503
Office Version
  1. 365
  2. 2019
  3. 2016
  4. 2010
Platform
  1. Windows
  2. MacOS
FYI, the Range statement will only accept 255 characters as its argument, so you'd have had to Union several ranges to do it your original way.
 

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