help with IF function to avoid #DIV/0! error

scolex

New Member
Joined
Jul 20, 2017
Messages
3
I have a formula that uses cells that are populated from a table.
Here is the formula =($A6*$E$3)/($J$3*$M$3*1056)
There are occasions where J3 is blank and I would like the formula to return a blank value.
 

Excel Facts

Difference between two dates
Secret function! Use =DATEDIF(A2,B2,"Y")&" years"&=DATEDIF(A2,B2,"YM")&" months"&=DATEDIF(A2,B2,"MD")&" days"
=iferror(($A6*$E$3)/($J$3*$M$3*1056),)

From what I read this is what you search.
 
Last edited:
Upvote 0
Thanks for the reply but that didn't change the result I still get the #DIV/0! error.
I tried changing the value to 0 instead of blank thinking maybe that would work but no luck.
I am a complete novice so please bear with me.
 
Upvote 0

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