How to find a value based on a COLUMNS criteria

[zazybang]

Hey guys, I need a formula that will find a value based on a columns criteria. EX: I am trying to find the opposite of INDEX(x,MATCH(, as it is used for finding values based on a rows criteria.

Sheet 1

Column A

Column B

<tbody>
</tbody>

Section: Ab

<tbody>
</tbody>

Name:	----ID:
X	C
Y	E

<tbody>
</tbody>

Column C

Column D

<tbody>
</tbody>

Section: Cd

<tbody>
</tbody>

Name:	----ID:
G	J
H	K

<tbody>
</tbody>

Sheet 2

Column A

<tbody>
</tbody>

Name

=FORMULA ID: (J)

=FORMULA ID: (C)

<tbody>
</tbody>

I am using an Index MATCH formula to get the name in the "=FORMULA" cells, what i require is an extension to this formula that will also write what section the ID came from EX: INDEX(MATCH())&"INSERT FORMULA HERE". So what it should say in Row 3 of sheet 2 is: "G, From Section Cd". While in row 4 it should say: "C, From Section Ab.".



Thanks for any help that is provided!

 

[Peter_SSs]

From what I can gather, you have the formula to get the name. See if this will help with the Section.

Here is my Sheet1

Excel Workbook
	A	B	C	D	E	F	G	H	I	J
1	Section: Ab		Section: Cd
2	Name:	----ID:	Name:	----ID:
3	X	C	G	J
4	Y	E	H	K
Sheet1

Formula in B2 is copied down.

Excel Workbook
	A	B
1	ID	Section
2	J	Section: Cd
3	C	Section: Ab
Sheet2

 

[zazybang]

Could you by chance break that formula down?

 

[Peter_SSs]

Could you by chance break that formula down?

Look at the example for ID = "J"
(COLUMN(Sheet1!A$1:J$1)-COLUMN(Sheet1!A$1)) produces an array of (column) numbers {0,1,2,3,4,5,6,7,8,9}
Divide by True/False (1/0) depending on whether A3:J4 in Sheet1 are equal to the ID. This produces a lot of #DIV/0! errors except for the one cell that does contain "J". That cell is in the 4th column of the Sheet1 array so it will leave the 4th number (3) in the above array of column numbers.
AGGREGATE(15,6 .... ,1) finds the smallest number in an array, ignoring errors. There is only one number left in the array and that is 3.
Then INDEX retrieves the value from the 3rd cell from the row 1 range in Sheet1 (Section: Cd)