Extract all cells from a column that meet criteria

Y

yaniv_sa

New Member
Joined
Nov 4, 2018
Messages
7
Hey,
I have a colum A (in sheet '2174') that have this kind of data:

1335001410
1335003990
1341000930
1341001790
1341001930
1341001990
1341002930
1341002990
1341003930
1841060182
1841060471
1842200760
1842201840
1842202841
1842203840
1842203841
1842205840
1842206840
1842207810

<colgroup><col></colgroup><tbody>
</tbody>

i want to extract only number that meet this crateria to the main sheet (colum A):
if > 1600000000 and last 3 digits 930 or <1600000000 and last 3 digits are 840.
with out VBA

the result should be like this:
1341000930
1341001930
1341002930
1341003930
1842201840
1842203840
1842205840
1842206840

<colgroup><col></colgroup><tbody>
</tbody>

I have tried may options with match and index but couldn't get it right.

please help.
 

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Hi

Your results don't comply with your criteria.
Example: 1341000930
Is >1600000000 but the last 3 digits are NOT 930.

 
Upvote 0
Okay. I also made a mistake.
Let me show you in boolean logic.
Arbeitsblatt mit dem Namen 'Tabelle1'
ABCD
1NumberLast 3 digits<1600000000 AND =840>1600000000 AND =930
21335001410410FALSCHFALSCH
31335003990990FALSCHFALSCH
41341000930930FALSCHFALSCH
51341001790790FALSCHFALSCH
61341001930930FALSCHFALSCH
71341001990990FALSCHFALSCH
81341002930930FALSCHFALSCH
91341002990990FALSCHFALSCH
101341003930930FALSCHFALSCH
111841060182182FALSCHFALSCH
121841060471471FALSCHFALSCH
131842200760760FALSCHFALSCH
141842201840840FALSCHFALSCH
151842202841841FALSCHFALSCH
161842203840840FALSCHFALSCH
171842203841841FALSCHFALSCH
181842205840840FALSCHFALSCH
191842206840840FALSCHFALSCH
201842207810810FALSCHFALSCH

<tbody>
</tbody>

ZelleFormel
B2=--RIGHT([@Number],3)
C2=AND([@Number]<1600000000,[@[Last 3 digits]]=840)
D2=AND([@Number]>1600000000,[@[Last 3 digits]]=930)

<tbody>
</tbody>
Verwendete Systemkomponenten: [Windows (32-bit) NT 6.01] MS Excel 2016
Diese Tabelle wurde mit Tab2Html (v2.6.0) erstellt. ©Gerd alias Bamberg

<tbody>
</tbody>

FALSCH is german for FALSE.
No number meets your criteria.
 
Upvote 0

Book1
A
21335001410
31335003990
41341000930
51341001790
61341001930
71341001990
81341002930
91341002990
101341003930
111841060182
121841060471
131842200760
141842201840
151842202841
161842203840
171842203841
181842205840
191842206840
201842207810
2174



Book1
A
11600000000
2930
3840
48
51341000930
61341001930
71341002930
81341003930
91842201840
101842203840
111842205840
121842206840
main


shift-del is right. We need to change the 1600000000 test in accordance with the results you want to obtain.


In A4 of main control+shift+enter, not just enter:

=SUM(IF('2174'!A2:A20<A1,IF(RIGHT('2174'!A2:A20,3)+0=A2,1))+IF('2174'!A2:A20>A1,IF(RIGHT('2174'!A2:A20,3)+0=A3,1)))

In A5 of main control+shift+enter, not just enter, and copy down:

=IF(ROWS($A$5:A5)>$A$4,"",INDEX('2174'!$A$2:$A$20,SMALL(IF(('2174'!$A$2:$A$20 < $A$1)*(RIGHT('2174'!$A$2:$A$20,3)+0=$A$2)+('2174'!$A$2:$A$20 > $A$1)*(RIGHT('2174'!$A$2:$A$20,3)+0=$A$3),ROW('2174'!$A$2:$A$20)-ROW(INDEX('2174'!$A$2:$A$20,1,1))+1),ROWS($A$5:A5))))
 
Upvote 0
shift-del said:
Okay. I also made a mistake.
Let me show you in boolean logic.
Arbeitsblatt mit dem Namen 'Tabelle1'
ABCD
1NumberLast 3 digits<1600000000 AND =840>1600000000 AND =930
21335001410410FALSCHFALSCH
31335003990990FALSCHFALSCH
41341000930930FALSCHFALSCH
51341001790790FALSCHFALSCH
61341001930930FALSCHFALSCH
71341001990990FALSCHFALSCH
81341002930930FALSCHFALSCH
91341002990990FALSCHFALSCH
101341003930930FALSCHFALSCH
111841060182182FALSCHFALSCH
121841060471471FALSCHFALSCH
131842200760760FALSCHFALSCH
141842201840840FALSCHFALSCH
151842202841841FALSCHFALSCH
161842203840840FALSCHFALSCH
171842203841841FALSCHFALSCH
181842205840840FALSCHFALSCH
191842206840840FALSCHFALSCH
201842207810810FALSCHFALSCH

<tbody>
</tbody>

ZelleFormel
B2=--RIGHT([@Number],3)
C2=AND([@Number]<1600000000,[@[Last 3 digits]]=840)
D2=AND([@Number]>1600000000,[@[Last 3 digits]]=930)

<tbody>
</tbody>
Verwendete Systemkomponenten: [Windows (32-bit) NT 6.01] MS Excel 2016
Diese Tabelle wurde mit Tab2Html (v2.6.0) erstellt. ©Gerd alias Bamberg

<tbody>
</tbody>

FALSCH is german for FALSE.
No number meets your criteria.
Click to expand...

view
view

it looks o.k. to me.
view

https://drive.google.com/file/d/1y-k2pdSEKC1IkSgFxQuqufxmsEyqZ4KO/view?usp=sharing
 
Upvote 0
Aladin Akyurek said:
A
21335001410
31335003990
41341000930
51341001790
61341001930
71341001990
81341002930
91341002990
101341003930
111841060182
121841060471
131842200760
141842201840
151842202841
161842203840
171842203841
181842205840
191842206840
201842207810

<colgroup><col style="width: 25pxpx"><col></colgroup><thead>
</thead><tbody>
</tbody>
2174​

A
11600000000
2930
3840
48
51341000930
61341001930
71341002930
81341003930
91842201840
101842203840
111842205840
121842206840

<colgroup><col style="width: 25pxpx"><col></colgroup><thead>
</thead><tbody>
</tbody>
main​

shift-del is right. We need to change the 1600000000 test in accordance with the results you want to obtain.


In A4 of main control+shift+enter, not just enter:

=SUM(IF('2174'!A2:A20<a1,if(right('2174'!a2:a20,3)+0=a2,1))+if('2174'!a2:a20>A1,IF(RIGHT('2174'!A2:A20,3)+0=A3,1)))

In A5 of main control+shift+enter, not just enter, and copy down:

=IF(ROWS($A$5:A5)>$A$4,"",INDEX('2174'!$A$2:$A$20,SMALL(IF(('2174'!$A$2:$A$20 < $A$1)*(RIGHT('2174'!$A$2:$A$20,3)+0=$A$2)+('2174'!$A$2:$A$20 > $A$1)*(RIGHT('2174'!$A$2:$A$20,3)+0=$A$3),ROW('2174'!$A$2:$A$20)-ROW(INDEX('2174'!$A$2:$A$20,1,1))+1),ROWS($A$5:A5))))
Click to expand...


Thank you
i got an error in:
=SUM(IF('2174'!A2:A20<a1,if(right('2174'!a2:a20,3)+0=a2,1))+if('2174'!a2:a20>A1,IF(RIGHT('2174'!A2:A20,3)+0=A3,1)))

when i have trid to add "," A20,A1 i get
304000000

<tbody>
</tbody>

the condition should be =OR(AND(B2<1600000000,VALUE(RIGHT(B2,3))=930),AND(B2>1600000000,VALUE(RIGHT(B2,3))=840))

can i do it in one cell (the table starts with a1 title, a2 data).

I have tried to do it like:
=IF(ROWS($A$5:A5)>$A$4,"",INDEX('2174'!A:A,SMALL(IF(('2174'!A:A < $A$1)*(RIGHT('2174'!A:A,3)+0=$A$2)+('2174'!A:A > $A$1)*(RIGHT('2174'!A:A,3)+0=$A$3),ROW('2174'!A:A)-ROW(INDEX('2174'!A:A,1,1))+1),ROWS($A$5:A5))))

with control+shift+enter



</a1,if(right('2174'!a2:a20,3)+0=a2,1))+if('2174'!a2:a20></a1,if(right('2174'!a2:a20,3)+0=a2,1))+if('2174'!a2:a20>
 
Upvote 0
If you are familiar with Power Query then you can use this M-Code.

Code: 
let
    Source = Excel.CurrentWorkbook(){[Name="tbl_Data"]}[Content],
    #"Changed Type" = Table.TransformColumnTypes(Source,{{"Number", Int64.Type}}),
    #"Duplicated Column" = Table.DuplicateColumn(#"Changed Type", "Number", "Number - Kopie"),
    #"Extracted Last Characters" = Table.TransformColumns(#"Duplicated Column", {{"Number - Kopie", each Text.End(Text.From(_, "de-DE"), 3), type text}}),
    #"Renamed Columns" = Table.RenameColumns(#"Extracted Last Characters",{{"Number - Kopie", "Last 3 digits"}}),
    #"Changed Type1" = Table.TransformColumnTypes(#"Renamed Columns",{{"Last 3 digits", Int64.Type}}),
    #"Filtered Rows" = Table.SelectRows(#"Changed Type1", each [Number] > 1600000000 and [Last 3 digits] = 840 or [Number] < 1600000000 and [Last 3 digits] = 930),
    #"Removed Columns" = Table.RemoveColumns(#"Filtered Rows",{"Last 3 digits"})
in
    #"Removed Columns"

Adapt Name="tbl_Data" to your need.
 
Upvote 0
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