Need Help with replacing invalid characters in a cell

[RoccoM]

I have a column that is basically a description field. It may or may not contain both invalid characters, and hidden, or non-printable characters.
I want to use regular expression to remove the invalid characters and replace them with " " (a space).
so for example a-z, A-Z 0-9 are acceptable all other characters, and hidden characters need to be replaced with a space.

I have already enabled Microsoft VBScript Regular Expressions 5.5 in VBA project.
How can I use regular expression to solve this?

Here is an example of what my data looks like. This happens to be in Column B

3Com, 3C1206-0 - SuperStack II Transceiver Module - Female AUI

3Com, 3C1206-3 - SuperStack II Transceiver Module - 10Base-T (UTP)

3Com, 3C1206-4 - SuperStack II Transceiver Module - Fan Out (Male AUI)

3Com, 3C1206-5 - SuperStack II Transceiver Module - Fibre Optic (ST)

3Com, 3C1206-7 - SuperStack II Transceiver Module - 10Base-FB

3Com, 3C16074 - SuperStack II Advanced RPS, Type 2 100W Power Module

3Com, 3C16411 - SuperStack III Baseline Dual Speed Hub, 24-Port

3Com, 3C16593A - SuperStack II Baseline Dual Speed Hub, 24 Port RJ45

3Com, 3C16610 - SuperStack II Dual Speed Hub 500 12x RJ45

3Com, 3C16683 - SuperStack II 100Base-TX Distance Extender Module

3Com, 3C16684 - SuperStack II 100Base-FX Distance Extender Module

3Com, 3C16685 - SuperStack II Dual Speed Hub 500 Manag.-M. for3C16610, 3C16611

3Com, 3C16700A - OfficeConnect Ethernet Hub 8/TPO, 8x 10BASE-T

3Com, 3C16701A - OfficeConnect Ethernet Hub 8C, 8x 10BASE-T

3Com, 3C16942A - SuperStack II Switch 3000 Ethernet, 12 x RJ45

3Com, 3C17111 - SuperStack III Switch 4300 Series, 100Base-FX Module

3Com, 3C17121 - SuperStack III Switch 4300 Series, 10/100/1000Base-T Module

3Com, 3C17131 - SuperStack III Switch 4300 Series, 1000Base-SX Module

3Com, 3C17203 - SuperStack III Switch 4400, 24 port 10BASE-T/100BASE-TX

<tbody>
</tbody>

Thank you,
Rocco

 

[Rick Rothstein]

And when the procedure is done, you want the first one to look like this, correct?

3Com 3C1206 0 SuperStack II Transceiver Module Female AUI

 

[RoccoM]

Yes
thanks for looking
Rocco

 

[CalcSux78]

Function CleanStr(ByVal str As String) As String
Dim n&, temp$
For n = 1 To Len(str)
    temp = Mid(str, n, 1)
    Select Case Asc(temp)
        Case 32, 48 To 57, 65 To 90, 97 To 122
            'do nothing
        Case Else
            str = Replace(str, temp, " ")
    End Select
Next n
CleanStr = WorksheetFunction.Trim(str)
End Function

 

[Rick Rothstein]

This does not use Regular Expressions, but it should be quite fast. What the code does is handle the entire column of data all at once. You did not say what column the data is in, so I assumed Column A (change the red highlighted column letters as needed). You also did not make clear if you wanted the original data overwritten or if you want the output in a different column. I assumed a different column and used Column B for the output (change the blue highlighted column letter as needed... you can even change it to the column letter containing the original data if you want that original data overwritten).

Sub AlphaNumericOnly()
  Dim R As Long, X As Long, Data As Variant
  Data = Range("[B][COLOR="#FF0000"][SIZE=2]A[/SIZE][/COLOR][/B]1", Cells(Rows.Count, "[B][COLOR="#FF0000"][SIZE=2]A[/SIZE][/COLOR][/B]").End(xlUp))
  For R = 1 To UBound(Data)
    For X = 1 To Len(Data(R, 1))
      If Mid(Data(R, 1), X, 1) Like "[!A-Za-z0-9]" Then Mid(Data(R, 1), X) = " "
    Next
    Data(R, 1) = Application.Trim(Data(R, 1))
  Next
  Range("[B][COLOR="#0000FF"][SIZE=2]B[/SIZE][/COLOR][/B]1").Resize(UBound(Data)) = Data
End Sub

 

[DanteAmor]

It seems that there is a list of invalid characters.
With the following you can eliminate them and leave all the caracreres that you could need.

Sub ReplaceSpecial()
    Dim wCell As Range, i As Long, special As Variant, wValue As String
    special = Array(127, 129, 141, 143, 144, 157, 160)
    For Each wCell In ActiveSheet.UsedRange.SpecialCells(xlCellTypeConstants, 23)
        wValue = wCell.Value
        For i = 0 To UBound(special)
            wValue = Replace(wValue, Chr(special(i)), "")
        Next
        For i = 0 To 31
            wValue = Replace(wValue, Chr(i), "")
        Next
        wCell.Value = wValue
    Next
End Sub

 

[Rick Rothstein]

It seems that there is a list of invalid characters.
With the following you can eliminate them and leave all the caracreres that you could need.

Sub ReplaceSpecial()
    Dim wCell As Range, i As Long, special As Variant, wValue As String
    special = Array(127, 129, 141, 143, 144, 157, 160)
    For Each wCell In ActiveSheet.UsedRange.SpecialCells(xlCellTypeConstants, 23)
        wValue = wCell.Value
        For i = 0 To UBound(special)
            wValue = Replace(wValue, Chr(special(i)), "")
        Next
        For i = 0 To 31
            wValue = Replace(wValue, Chr(i), "")
        Next
        wCell.Value = wValue
    Next
End Sub

I don't think your code does what the OP wants. Your code replaces only certain invalid characters, but the OP said...

I want to use regular expression to remove the invalid characters and replace them with " " (a space).
so for example a-z, A-Z 0-9 are acceptable all other characters, and hidden characters need to be replaced with a space.

Also see my question about his first example (Message#2) and the OP's response (Message#3).

 

[DanteAmor]

I don't think your code does what the OP wants. Your code replaces only certain invalid characters, but the OP said...

Also see my question about his first example (Message#2) and the OP's response (Message#3).

Oh, you're right, then I add the space

Sub ReplaceSpecial()
    Dim wCell As Range, i As Long, special As Variant, wValue As String
    special = Array(127, 129, 141, 143, 144, 157, 160)
    For Each wCell In ActiveSheet.UsedRange.SpecialCells(xlCellTypeConstants, 23)
        wValue = wCell.Value
        For i = 0 To UBound(special)
            wValue = Replace(wValue, Chr(special(i)), [COLOR=#ff0000]" "[/COLOR])
        Next
        For i = 0 To 31
            wValue = Replace(wValue, Chr(i), [COLOR=#ff0000]" "[/COLOR])
        Next
        wCell.Value = wValue
    Next
End Sub

I want to use regular expression to remove the invalid characters and replace them with " " (a space).

Let's see if they are the invalid characters , In any case, there is a macro to remove only invalid characters