Help with a complex formula

Richard U

Active Member
Joined
Feb 14, 2006
Messages
406
Office Version
  1. 365
  2. 2016
  3. 2010
  4. 2007
Platform
  1. Windows
I'm trying to break out customer data to several spreadsheets

It's working, but I think there must be an easier way


Here's what I have so far.....
The customer name is in column "E" and I want to pull the customer data into it's own sheet


=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",COUNT!$E$1:$E$5001,0)+0),0,0)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",COUNT!$E$1:$E$5001,0)+0),0,1)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",COUNT!$E$1:$E$5001,0)+0),0,2)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",COUNT!$E$1:$E$5001,0)+0),0,3)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",COUNT!$E$1:$E$5001,0)+0),0,4)

=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",COUNT!$E$1:$E$5001,0)+0),0,0)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",COUNT!$E$1:$E$5001,0)+0),1,0)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",COUNT!$E$1:$E$5001,0)+0),2,0)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",COUNT!$E$1:$E$5001,0)+0),3,0)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",COUNT!$E$1:$E$5001,0)+0),4,0)


et cetera....

Is there a way of designing the formula where the offset rows and columns will automatically increment?
 

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ugh, sorry....

Correction...

=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",Customer!$E$1:$E$5001,0)+0),0,0)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",Customer!$E$1:$E$5001,0)+0),0,1)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",Customer!$E$1:$E$5001,0)+0),0,2)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",Customer!$E$1:$E$5001,0)+0),0,3)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",Customer!$E$1:$E$5001,0)+0),0,4)

=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",Customer!$E$1:$E$5001,0)+0),0,0)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",Customer!$E$1:$E$5001,0)+0),1,0)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",Customer!$E$1:$E$5001,0)+0),2,0)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",Customer!$E$1:$E$5001,0)+0),3,0)
=OFFSET(INDIRECT("Customer!A" & MATCH("AB*",Customer!$E$1:$E$5001,0)+0),4,0)
 
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