Sum of columns

chunu

Board Regular
Joined
Jul 5, 2012
Messages
99
Office Version
  1. 2013
Platform
  1. Windows
  2. Mobile
hi,
I want sum of f2:h2 with the following formula, if i remove .value=.value , formula works fine but with .value=.value
only summing f2:g2
Please help.

Code:
With Range("d2").Formula = "=Sum(f2:h2)"
.Value = .Value
     End With

Thanks
 

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Try this:
Code:
Range("D2").Value = Application.WorksheetFunction.Sum(Range("F2:H2"))
 
Last edited:
Upvote 0
Try

Code:
Sub MM1()
With Range("d2")
    .Formula = "=Sum(f2:h2)"
    .Value = .Value
End With
End Sub
 
Upvote 0
What would be the logic behind putting a formula in the cell get the results you want and then remove the formula. Why not use my solution? Just wondering.

Code:
Sub MM1()
With Range("d2")
    .Formula = "=Sum(f2:h2)"
    .Value = .Value
End With
End Sub
[/QUOTE]
 
Upvote 0
I agree....would only do it if there was other cells impacted by that formula !!
 
Upvote 0
Try this:
Code:
Range("D2").Value = Application.WorksheetFunction.Sum(Range("F2:H2"))


Hi,
Thanks for reply
this sum only F2 & G2, H2 not picked
For some reason i want to remove formula after result.
thanks
 
Upvote 0
Hi,
Thanks for reply
this sum only F2 & G2, H2 not picked
The suggestion by My Aswer Is This includes the sum of all 3 cells for me.
BTW, did you also try Michael M's suggestion?


What would be the logic behind putting a formula in the cell get the results you want and then remove the formula. Why not use my solution? Just wondering.
A couple of reasons come to mind for me.

1. The OP was trying to use the idea of formula & replace so the suggestion along those lines indicates what was wrong with the OP's syntax (that is, a learning exercise on that syntax)


2. Relates to coding style/preference. The formula & replace lends itself immediately to the situation of a larger range of sums simply by changing
Code:
With Range("D2:D1000")
whereas the WorksheetFunction approach needs to be changed to Formula/Replace or Evaluate or building a loop (which would be considerably slower as the range gets larger)

Note, I am not suggesting that your solution here was wrong or inferior, just answering your query.
 
Last edited:
Upvote 0
Hi,
sorry guys it was my mistake , formula was in wrong position.
Thanks you all for your help.
 
Upvote 0

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