Maybe:
Code:=IF(Sheet1!$B6<>"", IF(MOD(ROW(Sheet1!A6),2)=0,Sheet1!$A5,""))
In column A every two cells are merged (A1 with A2, A3 with A4 etc...) so my formula only works properly for odd number rows. I need the below to use the value from the cell above if A6 is empty and so on.
=IF(Sheet1!$B6<>"", Sheet1!$A6,"")
Maybe:
Code:=IF(Sheet1!$B6<>"", IF(MOD(ROW(Sheet1!A6),2)=0,Sheet1!$A5,""))
Joe
When I was a young man I knew everything. Now that I'm older, I realize I know very little, and what I do know, I tend to forget!
Maybe
=IF(Sheet1!$A6="",Sheet1!$A5,Sheet1!A6)
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Running Office 365 on Win 10
Also did not work for what I'm trying to do but maybe it's my fault as maybe I wasn't clear enough with what I need. Ignore my first post and see the examples below. I need a formula to output the same results as in Sheet2.
In Sheet2 Column B I'm using the formula and it works perfectly. =IF(Sheet1!$B1<>"", Sheet1!$B1,"")
I need some help with the column A formula as the following only works with odd number rows. =IF(Sheet1!$B1<>"", Sheet1!$A1,"")
Sheet1 A B 1 Name1 500 2 3 Name2 4 5 Name3 600 6 300 7 Name4 8 400
Sheet2 A B 1 Name1 500 2 3 4 5 Name3 600 6 Name3 300 7 8 Name4 400
In cell A1 of Sheet2, try this formula and copy down.
=IF(Sheet1!B1="","",LOOKUP("zzz",Sheet1!A$1:A1))
Hope this helps, good luck.
Peter
Excel 365 - Windows 10
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That sort of indicates that in fact your data & results probably actually start on row 2 of each sheet, not row 1 as indicated in your tables in post 5? (Or else that formula is entered on row 2 of Sheet2 and copied up to row 1 which, while working actually creates a #REF ! error in the formula.
If everything (apart from any headings) actually starts on row 2, then you could also use this simpler version in A2 of Sheet2, copied down
=IF(Sheet1!B2="","",Sheet1!A1&Sheet1!A2)
Last edited by Peter_SSs; Sep 17th, 2019 at 06:08 AM.
Hope this helps, good luck.
Peter
Excel 365 - Windows 10
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