Removing hidden Chr within text, Chr63

USAMax

Well-known Member
Joined
May 31, 2006
Messages
843
Office Version
  1. 365
Platform
  1. Windows
I am using Excel 2010 and cleaning up some data and I have two cells that appear the same but when I compare ActiveCell to ActiveCell.Offset(1,0) they do not match.

When I broke it down I found the mid string that did not match and I got its value using

SndChr = Asc(Mid(ActiveCell.Offset(1, 0), StrVal, 1))
And this returned a value of 63.

I thought I was home free and I could search the string for Chr(63) but it does not find it.

If InStr(1, Cells(x, 1), Asc(63)) > 0 Then

Where am I going wrong?
 
Again agreed.

A sample of the data to be analysed would be an advantage to us all.

I'm fairly sure that this is a specific problem arrising from web derived data.
 
Upvote 0

Excel Facts

Which came first: VisiCalc or Lotus 1-2-3?
Dan Bricklin and Bob Frankston debuted VisiCalc in 1979 as a Visible Calculator. Lotus 1-2-3 debuted in the early 1980's, from Mitch Kapor.
This UDF might be a possibility.

I am not a VBa expert, so doubtless it can be improved.

Code:
Function CleanUnicode(rng As Range, _
                      Optional IncludeAscii As Boolean = True, _
                      Optional ShowAsSpace As Boolean = True, _
                      Optional TrimStr As Boolean = False) As String
    Dim n As Long
    Dim strClean As String, strChr As String
    
    strClean = rng
    
    For n = Len(strClean) To 1 Step -1
        strChr = Mid(strClean, n, 1)
        Select Case AscW(strChr)
            Case 8192 To 8207, 8234 To 8239, 8298 To 8303
               If ShowAsSpace Then
                    strClean = Replace(strClean, strChr, " ")
               Else
                    strClean = Replace(strClean, strChr, "")
                    n = Len(strClean)
               End If
        End Select
            
        If IncludeAscii Then
            Select Case Asc(strChr)
                Case 1 To 31, 127, 129, 141.143, 144, 157, 160
                   If ShowAsSpace Then
                        strClean = Replace(strClean, strChr, " ")
                   Else
                        strClean = Replace(strClean, strChr, "")
                        n = Len(strClean)
                   End If
            End Select
        End If
    Next
    If TrimStr Then
        CleanUnicode = WorksheetFunction.Trim(strClean)
    Else
        CleanUnicode = strClean
    End If
End Function

The default substitutes all non-printing characters,unicode spaces and invisible characters with a space, CHAR(32) e.g.
Code:
=CleanUnicode(A2)

The options as booleans are
1/. IncludeAscii > Default = True
2/. ShowAsSpace > Default = True
3/. TrimStr > Default = False

So this removes all non-printing characters and spaces
Code:
=CleanUnicode(A4,,FALSE)
And this trims the result if spaces are chosen
Code:
=CleanUnicode(A4,,FALSE)
i.e. The same as trimming the default function
Code:
=Trim(CleanUnicode(A2))

Try it out with this setup.
You will have to copy this abc??de??f for the string in A2, ExcelJeannie is returning ?s like your problem ...:eek:
Drag B2:D2 Down

Excel Workbook
ABCD
1StringLengthUDFNew Length
2abc??de ?f10abc de ?f10
3abc??de ?f15abc de ?f 15
4Abcefg7Abc efg7
5Abcefg7Abc efg7
Sheet1
 
Upvote 0

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