Checking For Palindromes

mianmazher

Active Member
Joined
Jan 24, 2004
Messages
412
Hi all forum Members

I want a formula to check for a number or text whether it is a palindrome
if in cell A1 I have 111 in B1 Its should say Its a aplindrome

similarlty for aba in cell A1

if I have 1111111233 in cell A1 in B1 I want a formula to say Its not Palindrome

Regards

Mian Mazher
 

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Here you are:

Code:
Function Palindrome(x) As Variant
    Dim y As String
    y = StrReverse(CStr(x))
    If y = CStr(x) Then
        Palindrome = "Palindrome"
    Else
        Palindrome = "Not a Palindrome"
    End If
End Function
 
Upvote 0
Hi Sir Aladin


I modified this formula

=IF(AND(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)=MID(A1,LEN(A1)+1-ROW(INDIRECT("1:"&LEN(A1))),1)),"Palindrome", "Try Again")


and entered without Ctrl+Shift+Enter


and its still working


U told to enter as array

Any difference between two?



Regards

Mian Mazher
 
Upvote 0
mianmazher said:
...


I modified this formula

=IF(AND(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)=MID(A1,LEN(A1)+1-ROW(INDIRECT("1:"&LEN(A1))),1)),"Palindrome", "Try Again")

In order to be able to say "Palindrome" or "Try Again"?

and entered without Ctrl+Shift+Enter


and its still working...

It still needs confirming with control+shift+enter. Try

xxxmmnnxxx

as input in A1.

If you'd like to see "Palindrome" and "Try Again" instead of TRUE and FALSE, here is a shorter way:

Just put -- before the original formula, that is:

=--AND(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)=MID(A1,LEN(A1)+1-ROW(INDIRECT("1:"&LEN(A1))),1))

and confirm with control+shift+enter.

Now custom format the formula cell as:

[=1]"Palindrome";[=0]"Try Again"
 
Upvote 0

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