Public Function WordCount

micglick

New Member
Joined
Feb 24, 2023
Messages
5
Office Version
  1. 365
  2. 2021
Platform
  1. Windows
Why does this Public Function not return the correct word count and instead provides a value of "0":
VBA Code:
Public Function CountWords(NumRange As Range) As Long
    Dim rCell As Range, lCount As Long
    For Each rCell In NumRange
        lCount = lCount + Len(Trim(rCell)) - Len(Replace(Trim(rCell), "", "")) + 1
    Next rCell
    CountWords = lCount
End Function
 
Last edited by a moderator:

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Try change to
VBA Code:
lCount = lCount + Len(Trim(rCell)) - Len(Replace(Trim(rCell), " ", "")) + 1
 
Upvote 0
Try this.

This line needed a space between the first set of double quotes.

lCount = lCount + Len(Trim(rCell)) - Len(Replace(Trim(rCell), " ", "")) + 1

VBA Code:
Public Function CountWords(NumRange As Range) As Long
   Dim rCell As Range, lCount As Long
   For Each rCell In NumRange
       lCount = lCount + Len(Trim(rCell)) - Len(Replace(Trim(rCell), " ", "")) + 1
   Next rCell
   CountWords = lCount
End Function
 
Upvote 0
Or try
VBA Code:
Public Function CountWords(NumRange As Range) As Long
Dim rCell As Range, lCount As Long
For Each rCell In NumRange
lCount = lCount + UBound(Split(Application.Trim(rCell.Value), " ")) + 1
Next rCell
CountWords = lCount
End Function
 
Upvote 0
You are very welcome
And thank you for the feedback
Be happy and safe
 
Upvote 0
Solution

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